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\usepackage[bookmarks, colorlinks=false, pdftitle={Mitschrift Analoge
Schaltungen Prof. Dr.-Ing. Schwarz}, pdfauthor={Fabian Kurz}, pdfsubject={Elektrotechnik}, pdfkeywords={Mathematik Elektrotechnik TU Dresden}, linkbordercolor={1 1 1}]{hyperref}
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\date{Zuletzt aktualisiert:\\\today}
\author{Fabian~Kurz\\\href{http://fkurz.net/}{http://fkurz.net/}}
\title{Analoge Schaltungen -- WS 05/06\\Prof. Dr.-Ing. Schwarz, TU Dresden\\Mitschrift}
\begin{document}
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\setlength{\parindent}{0pt}
\maketitle
\pagenumbering{Roman}
\tableofcontents
\newpage
\chapter{Bauelementemodelle}
\pagenumbering{arabic}

Ein Bauelementemodell ist ein Netzwerk, das zu einem gegebenen Bauelement ein
"aquivalentes Klemmenverhalten hat.

\section{Modelle}

\begin{minipage}{8cm}
\center
Eintore (Zweipole)

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\put(17,15){\makebox(0,0)[r]{$U$}}
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\multiput(40,0)(30,0){2}{\line(0,1){30}}
\end{picture}

\end{minipage}%
\begin{minipage}{8cm}
\center
Zweitore (Dreipole)

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\put(94,15){\makebox(0,0)[l]{$U_2$}}
\end{picture}
\end{minipage}%

\subsubsection*{Beispiele}

\bigskip

\begin{minipage}{8cm}
\center
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\thinlines

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\end{picture}
\end{minipage}%
\begin{minipage}{8cm}
\center

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\put(100,0){\circle*{2}}
\put(100,40){\line(0,1){20}}
\put(100,60){\line(1,0){20}}

\put(90,0){  % das ganze verschoben
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\put(90,40){\line(0,1){20}}
\put(90,60){\line(1,0){20}}
} % bis hier
\end{picture}
\end{minipage}%

\subsubsection*{Beschreibung}

\begin{minipage}{8cm}
\center
1 Gleichung

$\rightarrow$ Zweig im Netzwerk

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\put(8,63){\makebox(0,0)[b]{$I$}}

\end{picture}

\end{minipage}%
\begin{minipage}{8cm}
\center
2 Gleichungen

$\rightarrow$ 2 gekoppelte Zweige im Netzwerk

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\put(97,65){\makebox(0,0)[b]{$I_2$}}
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\end{minipage}%

\bigskip

\begin{description}
\item[Gro"ssignal-Modell:] Modelliert das Klemmenverhalten in einem weiten
Arbeitsbereich, i.d.R. nichtlinear.
\item[Kleinsignal-Modell:] Modelliert das Klemmenverhalten in der Umgebung
eines Arbeitspunktes $\rightarrow$ linear.
\end{description}

\newpage
\section{Zweipole}
\subsection*{Gro"ssignalmodelle}
\begin{center}
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\put(8,8){\makebox(0,0)[b]{$I$}}
\end{picture}
\qquad $f(U,I) = 0$

\bigskip

$\swarrow$ \hspace{6cm} $\searrow$
\end{center}

\begin{minipage}{8cm}
\center
$I = Y(U)$

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\begin{minipage}{8cm}
\center
$U = Z(I)$

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\put(50,2){\makebox(0,0){$Z(I)$}}
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\end{minipage}%

\subsection*{Kleinsignalmodelle}

\begin{minipage}{8cm}
\center
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\put(16,83){\makebox(0,0)[r]{$I$}}
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\put(93,65){\makebox(0,0)[c]{$A$}}
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\end{minipage}%
\begin{minipage}{8cm}
\center \[U = U_A +  u, \qquad I = I_A + i\]
(Koordinatenverschiebung)

\bigskip 


$U_A$, $I_A$: Spannung/Strom im Arbeitspunkt

\end{minipage}%

\begin{minipage}{8cm}
\begin{align*}
I &= I_A + i = Y(U_A + u)\\
 &=  \underbrace{Y(U_A)}_{I_A} + \left.\frac{dY}{dU}\right|_{U_A} \cdot u +
\cdots
\end{align*}
\end{minipage}%
\begin{minipage}{8cm}
\begin{align*}
U &= U_A + u = Z(I_A + i)\\
 &=  \underbrace{Z(I_A)}_{U_A} + \left.\frac{dZ}{dI}\right|_{I_A} \cdot i +
\cdots
\end{align*}
\end{minipage}%
\begin{center}lineare N"aherung
\end{center}
\begin{minipage}{8cm}
\begin{align*}
I &= I_A + i = I_A + g_D \cdot  u\\[1ex]
g_D &= \left.\frac{dI}{dU}\right|_{U_A} = \left.\frac{dY(U)}{dU}\right|_{U_A}
\end{align*}
\end{minipage}%
\begin{minipage}{8cm}
\begin{align*}
U &= U_A + u = U_A + r_D \cdot  i\\[1ex]
r_D &= \left.\frac{dU}{dI}\right|_{I_A} = \left.\frac{dZ(I)}{dI}\right|_{I_A}
\end{align*}
\end{minipage}%

\begin{center}Schaltungsmodell
\end{center}
\begin{minipage}{8cm}
\center
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$\ \ \ \Downarrow$

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\put(103,30){\makebox(0,0)[l]{$u$}}
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\end{minipage}%
\begin{minipage}{8cm}
\center

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$\Downarrow$

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\end{minipage}%

\paragraph{Beispiel:} Diode

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$I = I_s \left(e^{\frac U {U_T}} - 1\right) \approx I_s \cdot e^{\frac U {U_T}}$ \quad
f"ur\quad $I \gg I_s$

\bigskip

\[g_D = \left.\frac{dI}{dU}\right|_{U_A} = \frac{I_s \cdot
e^{\frac{U_A}{U_T}}}{U_T} = \frac{I_A}{U_T}, \qquad r_D = \frac 1 {g_D} =
\frac{U_T}{I_A} \]

\bigskip

zugeschnittene Gr"o"sengleichungen f"ur $I_s = 1\,\mathrm{pA}$, $U_T =
26\,\mathrm{mV}$:

\[g_D/\mathrm{S} = \frac{I_A/\mathrm{mA}}{26} \qquad r_D/\Omega =
\frac{26}{I_A/\mathrm{mA}}\]

\section{Zweitore}
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\end{picture}
\end{minipage}%
\begin{minipage}{6cm}
\begin{align*}
Y_1 & = F_1(X_1, X_2)\\
Y_2 & = F_2(X_1, X_2)
\end{align*}
\end{minipage}%
\begin{minipage}{5cm}\center
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\put(97,65){\makebox(0,0)[b]{$I_2$}}
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\end{minipage}

\paragraph{Kleinsignalmodell:} $X_i =  X_{i1} + x_i$, \quad $Y_i =  Y_{i1} +
y_i$, \quad $i = 1,2$
\begin{align*}
Y_1 &= \cancel{Y_{1A}} + y_1 =
\cancel{\underbrace{F_1(X_{1A},X_{2A})}_{Y_{1A}}} +
\left.\frac{\partial F_1}{\partial X_1}\right|_A \cdot x_1 +
\left.\frac{\partial F_1}{\partial X_2}\right|_A \cdot x_2 + \cdots \\
Y_2 &= \cancel{Y_{2A}} + y_2 = 
\cancel{\underbrace{F_2(X_{1A},X_{2A})}_{Y_{2A}}} +
\left.\frac{\partial F_2}{\partial X_1}\right|_A \cdot x_1 +
\left.\frac{\partial F_2}{\partial X_2}\right|_A \cdot x_2 + \cdots 
\end{align*}

\begin{minipage}{8cm}
\begin{empheq}[innerbox=\fbox]{align*}
\quad y_1 &= k_{11} \cdot x_1 + k_{12} \cdot x_2 \vphantom{\Big|} \quad \\
\quad y_2 &= k_{21} \cdot x_1 + k_{22} \cdot x_2 \vphantom{\Big|} \quad
\end{empheq}
\end{minipage}%
\begin{minipage}{8cm}
$\rightarrow$ lineare Zweipolbeschreibung
\end{minipage}

\subsubsection*{Leitwertbeschreibung}
\begin{minipage}{6cm}
\begin{align*}
I_1 & = Y_1(U_1, U_2)\\
I_2 & = Y_2(U_1, U_2)
\end{align*}
\end{minipage}%
\begin{minipage}{4cm}

\begin{picture}(50,45)
\put(9,20){\circle{2}}
\put(10,20){\line(1,0){20}}
\thicklines
\put(30,10){\line(0,1){20}}
\thinlines
\put(30,20){\line(1,1){10}}
\put(37,13){\vector(1,-1){0}}
\put(30,20){\line(1,-1){10}}
\put(40,1){\line(0,1){9}}
\put(40,00){\circle{2}}
\put(40,40){\circle{2}}
\put(40,30){\line(0,1){9}}
\qbezier(20,15)(20,5)(35,5)
\put(35,5){\vector(1,0){0}}
\put(08,0){$U_{BE}$}
\put(0,25){\vector(1,0){15}}
\put(7.5,27){\makebox(0,0)[b]{$I_B$}}
\put(45,45){\vector(0,-1){15}}
\put(48.5,37.5){\makebox(0,0)[l]{$I_B$}}
\qbezier(62,40)(70,20)(62,0)
\put(62,0){\vector(-1,-3){0}}
\put(68,20){\makebox(0,0)[l]{$U_{CE}$}}
\end{picture}

\end{minipage}%
\begin{minipage}{6cm}
\begin{align*}
I_B & = Y_1(U_{BE}, U_{CE})\\
I_C & = Y_2(U_{BE}, U_{CE})
\end{align*}
\end{minipage}

\bigskip

Kleinsignalmodell
\begin{align*}
i_1 &= y_{11} \cdot u_1 + y_{12} \cdot u_2  & i_B &= g_{BE} \cdot u_{BE} +
g_{\nu} \cdot u_{CE} \\
i_2 &= y_{21} \cdot u_1 + y_{22} \cdot u_2 & i_{C} &= g_m \cdot u_{BE} + g_{CE}
\cdot u_{CE}
\end{align*}
\begin{align*}
g_{BE} &=  \left.\frac{\partial I_B}{\partial U_{BE}}\right|_{A} & 
g_{\nu} &=  \left.\frac{\partial I_B}{\partial U_{CE}}\right|_{A} \\
g_{m} &=  \left.\frac{\partial I_C}{\partial U_{BE}}\right|_{A} & 
g_{CE} &=  \left.\frac{\partial I_C}{\partial U_{CE}}\right|_{A} 
\end{align*}

\begin{center}
\begin{picture}(245,80)
\multiput(19,0)(0,60){2}{\circle{2}}
\multiput(20,0)(0,60){2}{\line(1,0){90}}
\multiput(135,0)(0,60){2}{\line(1,0){90}}
\multiput(226,0)(0,60){2}{\circle{2}}

\multiput(70,0)(25,0){2}{
\multiput(40,0)(0,40){2}{\line(0,1){20}}
\multiput(40,20)(-10,10){2}{\line(1,1){10}}
\multiput(40,20)(10,10){2}{\line(-1,1){10}}
\put(30,30){\line(1,0){20}}
}

\multiput(50,0)(0,60){2}{\circle*2}
\multiput(50,0)(0,40){2}{\line(0,1){20}}
\multiput(45,20)(0,20){2}{\line(1,0){10}}
\multiput(45,20)(10,0){2}{\line(0,1){20}}
\put(43,30){\makebox(0,0)[r]{$g_{BE}$}}
\put(100,30){\makebox(0,0)[r]{$g_{\nu} u_{CE}\Big\downarrow$}}

\put(19,57){\vector(0,-1){54}}
\put(17,30){\makebox(0,0)[r]{$u_{BE}$}}
\put(226,57){\vector(0,-1){54}}
\put(228,30){\makebox(0,0)[l]{$u_{CE}$}}
\put(0,60){\vector(1,0){16}}
\put(8,63){\makebox(0,0)[b]{$i_B$}}
\put(245,60){\vector(-1,0){16}}
\put(238,63){\makebox(0,0)[b]{$i_{C}$}}
\put(145,30){\makebox(0,0)[l]{$\Big\downarrow g_mu_{BE}$}}

\multiput(195,0)(0,40){2}{\line(0,1){20}}
\multiput(195,0)(0,60){2}{\circle*2}
\multiput(190,20)(0,20){2}{\line(1,0){10}}
\multiput(190,20)(10,0){2}{\line(0,1){20}}
\put(203,30){\makebox(0,0)[l]{$g_{CE}$}}
\end{picture}
\end{center}

s. Folie: "`BPT/FET-Modelle"'

\bigskip


\begin{minipage}{8cm}
\center
\textbf{Y-Beschreibung}
\[i_B = g_{BE} \cdot u_{BE}\]
\[\boxed{\vphantom{\int}i_C = g_m \cdot u_{BE} } + g_{CE} \cdot u_{CE}\]
Hauptsteuergleichung \hspace*{2cm}

\end{minipage}%
\begin{minipage}{8cm}
\center
\textbf{H-Beschreibung}
\[u_{BE}= r_{BE} \cdot i_{B}\]
\[\boxed{\vphantom{\int}i_C = b   \cdot i_{B} } + g_{CE} \cdot u_{CE}\]
Hauptsteuergleichung \hspace*{2cm}
\end{minipage}

\bigskip

\[\text{Zusammenhang: \quad }g_m = \frac{b}{r_{BE}},\quad g_{BE} = \frac 1 {r_{BE}}\]


\begin{minipage}{8cm}
\begin{picture}(215,80)
\multiput(29,0)(0,60){2}{\circle2}
\multiput(60,0)(0,40){2}{\line(0,1){20}}
\multiput(55,20)(10,0){2}{\line(0,1){20}}
\multiput(55,20)(0,20){2}{\line(1,0){10}}
\put(30,60){\line(1,0){30}}
\put(5,60){\vector(1,0){20}}
\put(15,67){\makebox(0,0){$i_B$}}
\put(29,58){\vector(0,-1){56}}
\put(30,0){\line(1,0){155}}
\multiput(125,0)(0,40){2}{\line(0,1){20}}
\multiput(125,20)(-10,10){2}{\line(1,1){10}}
\multiput(125,20)(10,10){2}{\line(-1,1){10}}
\put(115,30){\makebox(0,0)[r]{$g_mu_{BE}\Big\downarrow$}}
\put(53,30){\makebox(0,0)[r]{$g_{BE}$}}
\put(27,30){\makebox(0,0)[r]{$u_{BE}$}}
\put(115,30){\line(1,0){20}}
\multiput(155,0)(0,40){2}{\line(0,1){20}}
\multiput(150,20)(10,0){2}{\line(0,1){20}}
\multiput(150,20)(0,20){2}{\line(1,0){10}}
\put(125,60){\line(1,0){60}}
\put(162,30){\makebox(0,0)[l]{$g_{CE}$}}
\put(186,58){\vector(0,-1){56}}
\multiput(186,0)(0,60){2}{\circle2}
\multiput(155,0)(0,60){2}{\circle*2}
\multiput(60,0)(65,00){2}{\circle*2}
\put(188,30){\makebox(0,0)[l]{$u_{CE}$}}
\put(210,60){\vector(-1,0){20}}
\put(202.5,67){\makebox(0,0){$i_C$}}
\end{picture}
\end{minipage}%
\begin{minipage}{8cm}
\begin{picture}(215,80)
\multiput(29,0)(0,60){2}{\circle2}
\multiput(60,0)(0,40){2}{\line(0,1){20}}
\multiput(55,20)(10,0){2}{\line(0,1){20}}
\multiput(55,20)(0,20){2}{\line(1,0){10}}
\put(30,60){\line(1,0){30}}
\put(5,60){\vector(1,0){20}}
\put(15,67){\makebox(0,0){$i_B$}}
\put(29,58){\vector(0,-1){56}}
\put(30,0){\line(1,0){155}}
\multiput(125,0)(0,40){2}{\line(0,1){20}}
\multiput(125,20)(-10,10){2}{\line(1,1){10}}
\multiput(125,20)(10,10){2}{\line(-1,1){10}}
\put(115,30){\makebox(0,0)[r]{$b\cdot i_B\Big\downarrow$}}
\put(53,30){\makebox(0,0)[r]{$r_{BE}$}}
\put(27,30){\makebox(0,0)[r]{$u_{BE}$}}
\put(115,30){\line(1,0){20}}
\multiput(155,0)(0,40){2}{\line(0,1){20}}
\multiput(150,20)(10,0){2}{\line(0,1){20}}
\multiput(150,20)(0,20){2}{\line(1,0){10}}
\put(125,60){\line(1,0){60}}
\put(162,30){\makebox(0,0)[l]{$r_{CE}$}}
\put(186,58){\vector(0,-1){56}}
\multiput(186,0)(0,60){2}{\circle2}
\multiput(155,0)(0,60){2}{\circle*2}
\multiput(60,0)(65,00){2}{\circle*2}
\put(188,30){\makebox(0,0)[l]{$u_{CE}$}}
\put(210,60){\vector(-1,0){20}}
\put(202.5,67){\makebox(0,0){$i_C$}}
\end{picture}
\end{minipage}%

\bigskip

s. Folie: "`Transferkennlinien"'

\section{Anwendung der Modelle}
\paragraph{Beispiel:}Emitterschaltung

\begin{minipage}{11cm}
\center
\begin{picture}(295,160)
\put(0,25){ %%%%%%%%%%%%%%%%%%%% von hier bis zur vorletzten Zeile
\put(50,0){\line(0,1){60}}
\put(50,30){\circle{20}}
\put(38,30){\makebox(0,0)[r]{$u_e\Big\downarrow$}}
\multiput(50,60)(32,0){2}{\line(1,0){28}}
\multiput(78,53)(4,0){2}{\thicklines\line(0,1){14}}
\multiput(110,60)(0,40){2}{\line(0,1){20}}
\multiput(105,80)(10,0){2}{\line(0,1){20}}
\multiput(105,80)(0,20){2}{\line(1,0){10}}
\put(110,60){\circle*2}
\put(110,60){\line(1,0){30}}
\put(140,50){\thicklines\line(0,1){20}}
\put(140,60){\line(1,1){10}}
\put(140,60){\line(1,-1){10}}
\put(148,52){\vector(1,-1){0}}
\put(150,70){\line(0,1){10}}
\put(150,100){\line(0,1){20}}
\multiput(145,80)(10,0){2}{\line(0,1){20}}
\multiput(145,80)(0,20){2}{\line(1,0){10}}
\put(150,00){\line(0,1){50}}
\put(145,00){\line(1,0){10}}
\put(45,00){\line(1,0){10}}
\put(150,70){\line(1,0){38}}
\put(192,70){\line(1,0){38}}
\multiput(188,63)(4,0){2}{\thicklines\line(0,1){14}}
\put(230,0){\line(0,1){20}}
\put(230,40){\line(0,1){30}}
\put(220,30){\line(1,0){20}}
\put(225,0){\line(1,0){10}}
\put(230,30){\circle{20}}
\put(110,120){\line(1,0){60}}
\put(171,120){\circle{2}}
\multiput(150,70)(0,50){2}{\circle*{2}}
\put(175,120){\makebox(0,0)[l]{$U_{0C}$}}
\put(103,90){\makebox(0,0)[r]{$R_{B}$}}
\put(80,75){\makebox(0,0)[c]{$C_{1}$}}
\put(190,85){\makebox(0,0)[c]{$C_{2}$}}
\put(143,90){\makebox(0,0)[r]{$R_{C}$}}
\put(240,30){\makebox(0,0)[l]{$\Big\uparrow i_a$}}
\qbezier(95,55)(80,45)(65,55)
\put(65,55){\vector(-3,2){0}}
\put(80,42){\makebox(0,0)[c]{$U_{BEA}$}}
\put(130,56){\vector(0,-1){56}}
\put(128,30){\makebox(0,0)[r]{$U_{BE}$}}
\put(165,66){\vector(0,-1){66}}
\put(167,30){\makebox(0,0)[l]{$U_{CE}$}}
\put(215,66){\vector(0,-1){66}}
\put(213,30){\makebox(0,0)[r]{$u_a$}}
\put(110,10){
\qbezier(95,55)(80,45)(65,55)
\put(80,42){\makebox(0,0)[c]{$U_{CEA}$}}
}
\put(205,65){\vector(3,2){0}}
% u_E
\put(10,70){\vector(0,1){25}}
\put(8,80){\vector(1,0){25}}
\put(8,90){\makebox(0,0)[r]{$\scriptscriptstyle u_e$}}
\multiput(10,80)(10,0){2}{
\qbezier(0,0)(1.25,8)(2.5,8)
\qbezier(2.5,8)(3.75,8)(5,0)
}
\put(10,80){
\qbezier(5,0)(6.25,-8)(7.5,-8)
\qbezier(7.5,-8)(8.75,-8)(10,0)
}
\put(25,75){\vector(2,-1){25}}
% u_BE
\put(75,95){\vector(1,-1){30}}
\put(50,90){\vector(0,1){25}}
\put(48,92){\vector(1,0){25}}
\multiput(49,103)(2,0){10}{\line(1,0){1}}
\put(48,103){\makebox(0,0)[r]{$\scriptscriptstyle U_{BEA}$}}
\multiput(50,103)(10,0){2}{
\qbezier(0,0)(1.25,3)(2.5,3)
\qbezier(2.5,3)(3.75,3)(5,0)
}
\put(50,103){
\qbezier(5,0)(6.25,-3)(7.5,-3)
\qbezier(7.5,-3)(8.75,-3)(10,0)
}
% u_CE
\put(195,101){\vector(-3,-2){40}}
\put(210,95){\vector(0,1){25}}
\put(208,97){\vector(1,0){25}}
\multiput(209,108)(2,0){10}{\line(1,0){1}}
\put(208,108){\makebox(0,0)[r]{$\scriptscriptstyle U_{CEA}$}}
\multiput(210,108)(10,0){2}{
\qbezier(0,0)(1.25,-3)(2.5,-3)
\qbezier(2.5,-3)(3.75,-3)(5,0)
}
\put(210,108){
\qbezier(5,0)(6.25,3)(7.5,3)
\qbezier(7.5,3)(8.75,3)(10,0)
}
% u_a
\put(270,70){\vector(0,1){25}}
\put(268,80){\vector(1,0){25}}
\put(268,90){\makebox(0,0)[r]{$\scriptscriptstyle u_a$}}
\multiput(270,80)(10,0){2}{
\qbezier(0,0)(1.25,-11)(2.5,-11)
\qbezier(2.5,-11)(3.75,-11)(5,0)
}
\put(270,80){
\qbezier(5,0)(6.25,11)(7.5,11)
\qbezier(7.5,11)(8.75,11)(10,0)
}
\put(260,75){\vector(-2,-1){25}}
}  % bis hier
\put(100,7){\makebox(0,0)[c]{$\scriptstyle U_{BE} = U_{BEA} +
\underbrace{\scriptstyle u_{BE}}_{u_e}$}}
\put(190,7){\makebox(0,0)[c]{$\scriptstyle U_{CE} = U_{CEA} + u_{a}
\vphantom{\underbrace{}_{u_e}}$}}
\end{picture}
\end{minipage}%
\hfill
\begin{minipage}{4.5cm}

\begin{description}
\item[gegeben:] \hspace*{\fill} \\ \raggedright
$U_{0C} = 12\,\mathrm V$,
$U_{CEA} = 6\,\mathrm V$,
$B = 100$, $U_{BE0} =
0{,}6\,\mathrm V$, $R_C = 10\,\mathrm k\Omega$,\\
$C_1$, $C_2 \to \infty$
\item[gesucht:]\hspace*{\fill} \\
 $R_B$, $r_e$, $u_a(u_e,\, i_a)$
\end{description}
\end{minipage}
\newpage % :-/
\subsection{Gro"ssignalmodell (zur Arbeitspunkteinstellung)}
\paragraph{Anwendung:} Das Bauelement wird durch das Modell (Ersatzschaltung)
ersetzt $\to$ Netzwerk (i.d.R. nichtlinear) $\to$ Analyse

\bigskip

\begin{minipage}{7cm}
\center
\begin{picture}(180,100)
\put(30,0){\line(0,1){60}}
\put(30,30){\circle{20}}
\put(20,30){\makebox(0,0)[r]{$U_{BE0}\Big\downarrow$}}
\multiput(0,0)(60,0){2}{
\multiput(25,60)(10,0){2}{\line(0,1){20}}
\multiput(25,60)(0,20){2}{\line(1,0){10}}
\put(30,80){\line(0,1){20}}
}
\multiput(30,0)(0,100){2}{\line(1,0){130}}
\multiput(90,0)(0,100){2}{\circle*{2}}
\multiput(90,0)(0,40){2}{\line(0,1){20}}
\multiput(90,20)(-10,10){2}{\line(1,1){10}}
\multiput(90,20)(10,10){2}{\line(-1,1){10}}
\put(80,30){\line(1,0){20}}
\put(23,70){\makebox(0,0)[r]{$R_B$}}
\put(83,70){\makebox(0,0)[r]{$R_C$}}
\put(35,17.5){\vector(0,-1){15}}
\put(38,10){\makebox(0,0)[l]{$I_{BA}$}}
\put(11,50){\line(1,0){19}}
\put(10,50){\circle{2}}
\put(30,50){\circle*{2}}
\put(7,50){\makebox(0,0)[r]{$B$}}
\put(71,50){\line(1,0){19}}
\put(70,50){\circle{2}}
\put(90,50){\circle*{2}}
\put(67,50){\makebox(0,0)[r]{$C$}}
\put(75,48){\vector(0,-1){46}}
\put(72,30){\makebox(0,0)[r]{$\scriptstyle U_{CEA}$}}

\put(141,15){\line(1,0){19}}
\put(140,15){\circle{2}}
\put(160,15){\circle*{2}}
\put(137,15){\makebox(0,0)[r]{$E$}}

\put(100,30){\makebox(0,0)[l]{$\Big\downarrow B\cdot I_{BA}$}}
\put(160,0){\line(0,1){100}}
\put(160,50){\circle{20}}
\put(170,50){\makebox(0,0)[l]{$\Big\downarrow U_{0C}$}}
\end{picture}
\end{minipage}%
\hfill
\begin{minipage}{8cm}
\begin{minipage}{3.5cm}
\begin{empheq}[innerbox=\fbox]{align*}
\quad U_{BE} &= U_{BE0} \vphantom{\Big|} \quad \\
\quad I_C &= B \cdot I_B \vphantom{\Big|} \quad
\end{empheq}
\end{minipage}%
\begin{minipage}{4.5cm}
\center
\bigskip
\textbf{Transistormodell}

\footnotesize (Vernachl"a"sigung des Early-Effekts)
\end{minipage}

\bigskip

\end{minipage}  % naja ;)

\bigskip
\bigskip

\[I_{CA} = \frac{U_{0C}-U_{CEA}}{R_C} = \frac{6\,\mathrm V}{12\,\mathrm
k\Omega},\qquad I_{BA} = \frac{U_{0C} - U_{BE0}}{R_B} = \frac{I_{CA}}{B} = 6\,\mu\mathrm A  \]

\[\boxed{R_B = \frac{U_{0C} - U_{BEA}}{I_{BA}} = \frac{U_{0C} - U_{BE0}}{U_{0C} -
U_{CEA}} \cdot  B \cdot R_C = B\cdot R_C \cdot \frac{1 -
\frac{U_{BC0}}{U_{0C}}}{1-\frac{U_{CEA}}{U_{0C}}}}\]
\[R_B = B \cdot R_C \cdot \frac{1-\frac{0{,}6\,\mathrm V}{12\,\mathrm
V}}{1-\frac{6\,\mathrm V}{12\,\mathrm V}} = 1{,}9 \cdot B \cdot R_C =
1{,}9\,\mathrm M\Omega\]
\paragraph{Spezialfall:} $U_{0C} \gg U_{CE0} \rightarrow \frac{U_{CEA}}{U_{0C}}
= \frac 1 2 \quad \Rightarrow \quad \boxed{\ R_B \approx 2 \cdot B \cdot R_C \
\vphantom{|}}$

\subsection{Kleinsignalmodell (Analyse bei kleinen Aussteuerungen)}
\paragraph{Anwendung:}\quad

\begin{enumerate}
\item Ersetzen des Bauelements durch sein Kleinsignal-Ersatzschaltbild
\item Alle Konstantspannungs(-strom)quellen werden durch Kurzschluss (Leerlauf)
ersetzt\\ $\to$ Lineares Netzwerk mit Kleinsignalgr"o"sen
\end{enumerate}
\paragraph{Begr"undung:}\quad

\begin{minipage}{8cm}
\center
\begin{picture}(150,80)
\put(30,0){\line(0,1){60}}
\put(30,30){\circle{20}}
\put(20,30){\makebox(0,0)[r]{$U_{0C}$\Big\downarrow}}
\put(94,30){\makebox(0,0)[l]{$u = U_{0C} + RI$}}
\put(60,71){\makebox(0,0)[c]{$R$}}
\multiput(25,0)(61,0){2}{\line(1,0){10}}
\multiput(30,60)(40,0){2}{\line(1,0){20}}
\multiput(50,55)(0,10){2}{\line(1,0){20}}
\multiput(50,55)(20,0){2}{\line(0,1){10}}
\put(91,60){\circle{2}}
\put(91,58){\vector(0,-1){56}}
\put(110,60){\vector(-1,0){15}}
\put(105,65){\makebox(0,0)[c]{$I$}}
\end{picture}
\end{minipage}%
\begin{minipage}{8cm}
\center
\begin{picture}(150,80)
\put(0,-10){  % naja..
\put(80,10){\vector(0,1){70}}
\put(00,15){\vector(1,0){120}}
\put(20,10){\line(3,2){80}}
\put(78,71){\makebox(0,0)[r]{$U$}}
\put(110,8){\makebox(0,0)[c]{$I$}}
\put(78.5,50){\line(1,0){3}}
\put(84,50){\makebox(0,0)[l]{$U_{0C}$}}
\put(78.5,30){\line(1,0){3}}
\put(48,30){\vector(1,0){25}}
\put(50,28){\vector(0,1){25}}
\put(84,30){\makebox(0,0)[l]{$U_{A}$}}
\put(50,13.5){\line(0,1){3}}
\put(50,7){\makebox(0,0)[c]{$I_{A}$}}
\put(48,50){\makebox(0,0)[r]{$u$}}
\put(70,28){\makebox(0,0)[t]{$i$}}
\put(50,30){\circle*2}
\put(45,32){\makebox(0,0)[r]{$A$}}
}
\end{picture}
\end{minipage}%

\bigskip
\bigskip

\[U = U_A + u = U_{0C} + (I_A + i)\cdot R = \underbrace{U_{0C} + I_A \cdot
R}_{U_A} + i\cdot R\]

\bigskip

\begin{minipage}{3cm}
$\boxed{\ \vphantom{|} u = i \cdot R \ } \quad \Rightarrow$
\end{minipage}\hfill  
\begin{minipage}{12cm}
\center nach
Koordinatenverschiebung reiner Widerstand f"ur das Kleinsignal

$\to$
Strom/Spannungsquellen deaktivieren
\end{minipage}%  


\paragraph{Kleinsignalmodell:}
\begin{center}
\begin{picture}(450,70)
\put(100,0){   % verschoben in die Mitte bis %%%%%%%%%%%%
\multiput(29,0)(0,60){2}{\circle2}
\multiput(60,0)(0,40){2}{\line(0,1){20}}
\multiput(55,20)(10,0){2}{\line(0,1){20}}
\multiput(55,20)(0,20){2}{\line(1,0){10}}
\put(30,60){\line(1,0){30}}
%\put(5,60){\vector(1,0){20}}
%\put(15,67){\makebox(0,0){$i_B$}}
\put(29,58){\vector(0,-1){56}}
\put(30,0){\line(1,0){155}}
\multiput(125,0)(0,40){2}{\line(0,1){20}}
\multiput(125,20)(-10,10){2}{\line(1,1){10}}
\multiput(125,20)(10,10){2}{\line(-1,1){10}}
\put(115,30){\makebox(0,0)[r]{$g_mu_{e}\Big\downarrow$}}
\put(53,30){\makebox(0,0)[r]{$r_{BE}$}}
\put(27,30){\makebox(0,0)[r]{$u_{e}$}}
\put(115,30){\line(1,0){20}}
\multiput(155,0)(0,40){2}{\line(0,1){20}}
\multiput(150,20)(10,0){2}{\line(0,1){20}}
\multiput(150,20)(0,20){2}{\line(1,0){10}}
\put(125,60){\line(1,0){60}}
\put(162,30){\makebox(0,0)[l]{$g_{CE}$}}
\put(230,58){\vector(0,-1){56}}
\multiput(186,0)(0,60){2}{\circle2}
\multiput(155,0)(0,60){2}{\circle*2}
\multiput(60,0)(65,00){2}{\circle*2}
\put(232,30){\makebox(0,0)[l]{$u_{a}$}}
%\put(210,60){\vector(-1,0){20}}
%\put(202.5,67){\makebox(0,0){$i_C$}}
} % hier %%%%%%%%%%%%%%%%%%%

\multiput(128,0)(0,60){2}{\line(-1,0){70}}
\multiput(100,0)(0,40){2}{\line(0,1){20}}
\multiput(100,0)(0,60){2}{\circle*2}
\multiput(95,20)(10,0){2}{\line(0,1){20}}
\multiput(95,20)(0,20){2}{\line(1,0){10}}
\put(93,30){\makebox(0,0)[r]{$R_B$}}
\put(58,0){\line(0,1){60}}
\put(58,30){\circle{20}}
\put(47,30){\makebox(0,0)[r]{$u_e\Big\downarrow$}}
\put(68,63){\vector(1,0){15}}
\put(75.5,65){\makebox(0,0)[b]{$i_e$}}
\multiput(287,0)(0,60){2}{\line(1,0){70}}
\multiput(300,0)(0,40){2}{\line(0,1){20}}
\multiput(300,0)(0,60){2}{\circle*2}
\multiput(295,20)(10,0){2}{\line(0,1){20}}
\multiput(295,20)(0,20){2}{\line(1,0){10}}
\put(307,30){\makebox(0,0)[l]{$R_C$}}
\multiput(357,0)(0,40){2}{\line(0,1){20}}
\put(357,30){\circle{20}}
\put(347,30){\line(1,0){20}}
\put(367,30){\makebox(0,0)[l]{$\Big\uparrow i_a$}}
\end{picture}
\end{center}
\textbf{gegeben:} $u_e$, $i_a$,\quad \textbf{gesucht:} $i_c$, $u_a$ \hfill
NR: $r_{BE} = \frac{U_T}{I_{BA}} = %\frac{26\,\mathrm{mV}}{6\,\mu\mathrm A} = 
4{,}3\,\mathrm k\Omega, \quad g_m = \frac{I_{CA}}{U_T} =
%\frac{0{,}6\,\mathrm{mA}}{26\,\mathrm{mV}} =
23\,\mathrm{mS}$

\bigskip

\[i_e = \frac{u_e}{R_B\parallel r_{BE}} \quad \Rightarrow \quad r_e =
\frac{u_e}{i_e} = \frac{R_B \cdot  r_{BE}}{R_B + r_{BE}} = r_{BE}\]
\begin{align*}
u_a &= (-g_m \cdot  u_e + i_a) \cdot R_C \parallel r_{CE} &
\text{("Uberlagerungssatz)}\\
 &= -g_m u_e \cdot  R_C\parallel r_{CE} + i_a \cdot R_C\parallel r_{CE}
& \text{Annahme: } U_Y \to \infty \Rightarrow r_{CE} \to \infty \\
&= -g_m u_e R_C + i_a R_C = v \cdot u_e + r_a \cdot i_a & i_e = \frac 1
{r_e} u_e
\end{align*}

\begin{description}
\item[Verst"arkung:] $v = -g_m \cdot R_C = -23\,\mathrm{mS}\cdot 10\,\mathrm
k\Omega = - 230$
\item[Ausgangswiderstand:] $r_a \approx R_C \approx 10\,\mathrm k\Omega$
(\emph{Ohne} Early-Effekt!) 
\end{description}

Die nat"urliche Beschreibung des Verst"arkers ist die \emph{inverse
Hybridbeschreibung}.

\chapter{Methoden der Schaltungsanalyse}

\section{Netzwerkanalyse}
Da die wesentlichen aktiven Bauelemente durch gesteuerte Stromquellen
modelliert werden, wird die Knotenspannungsanalyse bevorzugt.
\paragraph{Voraussetzung:} Alle $U$-$I$-Relationen m"ussen in der Form


\begin{minipage}{7cm}
\center
$\boxed{\ \vphantom{\Big|} I = Y(U) \ }$ \qquad (Zweipole)
\end{minipage}%
\begin{minipage}{2cm}
\center bzw.
\end{minipage}%
\begin{minipage}{7cm}
\center
\begin{minipage}{4.5cm}
\begin{empheq}[innerbox=\fbox]{align*}
\quad I_1 &= Y_1(U_1,U_2) \vphantom{\Big|} \quad\\
\quad I_2 &= Y_2(U_1,U_2) \vphantom{\Big|} 
\end{empheq}
\end{minipage}%
\begin{minipage}{2.5cm}
\center
 (Vierpole)
\end{minipage}%
\end{minipage}%

vorliegen.
\begin{itemize}
\item[$\rightarrow$] Im Netzwerk nur noch unabh"angige oder spannungsgesteuerte
Stromquellen
\item[$\rightarrow$] Spannungssteuermodelle bevorzugt
\end{itemize}
\subsubsection*{Algorithmus}
\begin{enumerate}
\item Festlegen des Bezugsknoten (meist Masse)
\item Knotenspannungen einf"uhren
\item Knotengleichungen (Strombilanzen) unter Verwendung der $U$-$I$-Relationen
der Zweige aufstellen
\item Knotengleichungen l"osen
\item gesuchte Gr"o"sen berechnen
\end{enumerate}

\subsubsection*{Beispiel: Diodenschalter}
%(vlg. "Ubungsaufgabe 1.27)

\begin{minipage}{6cm}
\begin{picture}(150,130)
\put(19,75){\circle{2}}
\put(20,75){\line(1,0){20}}
\multiput(40,75)(24,24){2}{\line(1,1){14}}%ol
\multiput(49,94)(10,10){2}{\line(1,-1){10}}
\put(59,104){\line(-1,-3){5}}
\put(69,94){\line(-3,-1){14.5}}

\multiput(40,75)(24,-24){2}{\line(1,-1){14}}%ul
\multiput(49,56)(10,-10){2}{\line(1,1){10}}
\put(49,56){\line(3,-1){14.5}}
\put(59,66){\line(1,-3){5}}

\multiput(116,75)(-24,24){2}{\line(-1,1){14}}%or
\put(38,38){
\multiput(49,56)(10,-10){2}{\line(1,1){10}}
\put(49,56){\line(3,-1){14.5}}
\put(59,66){\line(1,-3){5}}
}
\multiput(116,75)(-24,-24){2}{\line(-1,-1){14}}%ol
\put(38,-38){
\multiput(49,94)(10,10){2}{\line(1,-1){10}}
\put(59,104){\line(-1,-3){5}}
\put(69,94){\line(-3,-1){14.5}}
}
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\put(78,75){\circle{20}}
\put(68,75){\line(1,0){20}}
\put(87,75){\makebox(0,0)[l]{$\Big\uparrow I_0$}}

\multiput(40,75)(76,0){2}{\circle*2}
\multiput(78,37)(0,76){2}{\circle*2}
\put(137,75){\circle{2}}
\put(116,75){\line(1,0){20}}
\put(0,75){\vector(1,0){15}}
\put(7.5,78){\makebox(0,0)[b]{$I_1$}}

\put(35,85){\makebox(0,0)[c]{\textcircled{\raisebox{-1pt}{1}}}}
\put(78,120){\makebox(0,0)[c]{\textcircled{\raisebox{-1pt}{2}}}}
\put(78,28){\makebox(0,0)[c]{\textcircled{\raisebox{-1pt}{3}}}}
\put(120,85){\makebox(0,0)[c]{\textcircled{\raisebox{-1pt}{0}}}}

\put(78,0){\makebox(0,0)[b]{$I_D = I_S\left(e^{U_D/U_T} -1\right)$}}
\end{picture}
\end{minipage}%
\begin{minipage}{10cm}
\begin{description}
\item[Gesucht:] $r_1 = \dfrac{dU_{10}}{dI_1}$
\item[Knotenspannungsanalyse:] Knotengleichungen
\begin{align*}
\text{\textcircled{\raisebox{-1pt}{1}}} &&
I_S\left(e^{\frac{U_1-U_3}{U_T}}-1\right) -
I_S\left(e^{\frac{U_2-U_1}{U_T}}-1\right) &= I_1\\
\text{\textcircled{\raisebox{-1pt}{2}}} &&
I_S\left(e^{\frac{U_2-U_1}{U_T}}-1\right) -
I_S\left(e^{\frac{U_2}{U_T}}-1\right) &= I_0\\
\text{\textcircled{\raisebox{-1pt}{3}}} &&
I_S\left(e^{\frac{U_1-U_3}{U_T}}-1\right) -
I_S\left(e^{-\frac{U_3}{U_T}}-1\right) &= I_0
\end{align*}
\end{description}
\end{minipage}%

Substitution: $e^{\frac{U_i}{U_T}} = x_i$, $i = 1,\,2,\,3$

\begin{align*}
\text{\textcircled{\raisebox{-1pt}{1}}} &&
\frac{x_1}{x_3} - \frac{x_2}{x_1} &= \frac{I_1}{I_2} \\
\text{\textcircled{\raisebox{-1pt}{2}}} &&
\frac{x_2}{x_1} + x_2 &= \frac{I_0}{I_S} + 2 & \Rightarrow \quad
x_2 &= \frac{\frac{I_0}{I_S} + 2}{1 + \frac 1 {x_1}}
\\
\text{\textcircled{\raisebox{-1pt}{3}}} &&
\frac{x_1}{x_3} + \frac{1}{x_3} &= \frac{I_0}{I_S} + 2 & \Rightarrow\quad
\frac{1}{x_3} &= \frac{\frac{I_0}{I_S} + 2}{1 + {x_1}}
\end{align*}
Einsetzen in \textcircled{\raisebox{-1pt}{1}} f"uhrt zu $x_1 = \dfrac{1+\frac{I_1}{I_0 +
2I_S}}{1 - \frac{I_1}{I_0 +2I_S}}$. Nach R"ucksubstitution und $\ln
\frac{1+x}{1-x} \approx 2x$ f"ur $x \ll 1$:
\[U_1 = U_T \cdot \ln \frac{1+\frac{I_1}{I_0 + 2I_S}}{1 - \frac{I_1}{I_0
+2I_S}} \approx U_T \frac{2I_1}{I_0 + 2I_S} = \left\{\begin{array}{ll}
\frac{2U_T}{I_0}\cdot I_1 & \text{f"ur } I_0 \gg I_S,\ I_1\\[2ex]
\frac{U_T}{I_S}\cdot I_1 & \text{f"ur } I_0=0
\end{array}\right.\]
Somit ergibt sich $r_1$ zu:
\[r_1 = \frac{dU_{10}}{dI_1} = \left\{\begin{array}{ll}
2\frac{U_1}{I_0} & \text{f"ur } I_0 \gg I_S,\ I_1\\[2ex]
\frac{U_T}{I_S} & \text{f"ur } I_3 = 0
\end{array} \right.\]

\section{Signalflu"sanalyse}

Siehe
\href{http://www.iee.et.tu-dresden.de/iee/ge/student/materialien/ST/folien/analyse/sigfl.pdf}{http://www.iee.et.tu-dresden.de/iee/ge/student/materialien/ST/folien/analyse/sigfl.pdf}

(11 Seiten).

% juppie. scheissarbeit gespart ;)

\chapter{Grundschaltungen}

\section{Grundmodell Spannungsverst"arker}

\begin{minipage}{6cm}\center
\begin{picture}(110,55)
\put(0,25){\vector(1,0){15}}
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\put(19,23){\vector(0,-1){16}}
\put(17,15){\makebox(0,0)[r]{$U_1 = U_e$}}
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\put(110,25){\vector(-1,0){15}}
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\put(94,15){\makebox(0,0)[l]{$U_2 = U_a$}}
\end{picture}
\end{minipage}%
\begin{minipage}{10cm}
\center \textbf{Gro"ssignalmodell} (inv. Hybridbeschreibung)
\begin{empheq}[innerbox=\fbox]{align*}
\quad I_1 &= H_1'(U_1,\,I_2) \vphantom{|} \quad\\
\quad U_2 &= H_2' (U_1,\,I_2) \vphantom{|} 
\end{empheq}
\end{minipage}%

\paragraph{Kleinsignalmodell:}  
\begin{empheq}[innerbox=\fbox]{align*}
\quad i_e &= g_e \cdot u_e + \alpha \cdot i_a \quad\\
\quad u_a &= v \cdot u_e + r_a \cdot i_a 
\end{empheq}

\bigskip
\smallskip

\begin{tabular}{@{}p{2.2cm}p{4.5cm}p{2.3cm}p{5.6cm}@{}}
$v = \left.\dfrac{u_a}{u_e}\right|_{i_a=0}$ & Leerlaufverst"arkung &
$r_a = \left.\dfrac{u_a}{i_a}\right|_{u_e=0}$ &
Kurzschluss-Ausgangswiderstand\\[5ex]
$g_e = \left.\dfrac{i_e}{u_e}\right|_{i_a=0}$ & Leerlauf-Eingangsleitwert &
$\alpha = \left.\dfrac{i_e}{i_a}\right|_{u_e=0}$ & Kurzschluss-Stromr"uckwirkung
\end{tabular}

\begin{minipage}{11cm}
\begin{picture}(200,100)
\color{grau}
\put(30,0){\line(0,1){60}}
\put(30,30){\circle{20}}
\put(20,30){\makebox(0,0)[r]{$u_G\Big\downarrow$}}
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\color{grau}
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\put(72,70){\vector(-1,0){0}}
\put(75,72){\makebox(0,0)[b]{$R_G$}}

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\put(72,-10){\vector(-1,0){0}}
\put(75,-12){\makebox(0,0)[t]{$-1/R_L$}}
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\put(10,63){\makebox(0,0)[b]{$u_G$}}
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\multiput(120,00)(0,60){2}{\circle*3}
\end{picture}
\end{minipage}%

\bigskip

\subsubsection*{Betriebsparameter}

\begin{itemize}
\item Betriebsverst"arkung: $v_B = \dfrac{u_a}{u_e} =
\dfrac{1}{1+\frac{r_a}{R_L}}$, bzw. $v_{B2} = \dfrac{u_a}{u_G}$
(ber"ucksichtigt $R_G$)
\item Betriebs-Eingangswiderstand: $r_{eB} = \dfrac{u_e}{i_e}$
\item Betriebs-Ausgangswiderstand: $r_a =\left.\dfrac{u_a}{i_a}\right|_{u_G=0}$
\end{itemize}

\section{Emitterschaltung}
\subsection{Gro"ssignalverhalten}

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\put(95,52){\makebox(0,0)[b]{$I_{a}=0$}}
\end{picture}
\end{minipage}%
\begin{minipage}{6cm}
\center
\textbf{Transferkennlinie:} $U_a = f(U_C)$
\[I_C = I_S \cdot e^{\frac{U_{BE}}{U_T}}\]
\[U_{BE} = U_e, \ U_a = U_{0C} -
I_C \cdot R_C\]
\[\boxed{\quad U_a = U_{0C} - I_S \cdot R_C \cdot e^{\frac{U_e}{U_T}}
\vphantom{\int^b_a}\quad}\]
\end{minipage}%
\begin{minipage}{5cm}
\hfill
\begin{picture}(110,110)
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\put(10,15){\vector(1,0){100}}
\put(17,90){\makebox(0,0)[r]{$U_a$}}
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\put(73,48){\makebox(0,0)[l]{$R_C$}}
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\end{minipage}

\paragraph{Eingangskennlinie:} \quad $\boxed{\quad I_e = I_B = \frac{I_S}{B_F} \cdot
e^{\frac{U_{e}}{U_T}} \quad}$
\subsubsection*{Aussteuerdiagramm:}

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\end{picture}
\end{minipage}%
\hfill
\begin{minipage}{10.5cm}
\[\boxed{\quad v = \left.\frac{dU_a}{dU_e}\right|_{AP} = -\frac{R_C\cdot
I_S}{U_T} \cdot e^{\frac{U_eA}{U_T}} = -\frac{R_C \cdot I_{CA}}{U_T} = -
\frac{U_{R_CA}}{U_T}  \quad}\]
\end{minipage}%

\subsection{Kleinsignalverhalten}

\begin{minipage}{6cm}
\center
\begin{picture}(160,125)
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\multiput(48,53)(4,0){2}{\thicklines\line(0,1){14}}
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\put(97,30){\makebox(0,0)[l]{$r_{BE}$}}

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\end{picture}
\end{minipage}%

\bigskip

\begin{align*}
v_{B_1} &= - \frac{g_m \cdot u_e \cdot R_2}{u_2} = -g_m \cdot R_2 = -
g_m(R_{CE}\parallel R_C \parallel R_L) && (\text{Gr"o"senordnung }10^2)\\
r_{e_B} &= R_B\parallel r_{BE} \approx r_{BE} && (11^0\,\mathrm k\Omega)\\
r_{a_B} &= r_{CE} \parallel R_C && (10^1\mathrm k\Omega)
\end{align*}

\subsection{Arbeitspunkteinstellung}

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\begin{tabular}{lp{4cm}p{4cm}p{5cm}}
& \bf Forderung & \bf Arbeitspunkt & \bf Aussteuerdiagramm
\tabularnewline\tabularnewline
1. & \raggedright Hohe Verst"arkung bei kleiner Aussteuerung & $U_{R_CA}$
m"oglichst gro"s & \\
& & &\qquad\begin{picture}(100,65)
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\\
2. & \raggedright Maximale Aussteuerung  & \raggedright Mitte des aktiven
Bereichs & \\
   & & &
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3. & Thermische Stabilit"at & $U_{CEA} \geq \frac{U_{0C}}{2}$ 
\end{tabular}

\subsection{Schaltungen zur Arbeitspunkteinstellung}

\paragraph*{Basisstromeinstellung:}
siehe 1.4
\subsubsection*{Emitterstromregelung}

\begin{minipage}{4.5cm}
\center
\begin{picture}(120,125)
\put(-40,0){
\multiput(70,60)(0,40){2}{\line(0,1){20}} %R2
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\multiput(65,80)(0,20){2}{\line(1,0){10}}
\multiput(70,00)(0,40){2}{\line(0,1){20}} %R1
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\begin{minipage}{5cm}
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\hfill
\begin{minipage}{6cm}
\subsubsection*{Entwurfsbeispiel:}\raggedright gegeben: $U_{BE0} = 0{,}6\,\mathrm V$, $B = 100$,
$I_{CA} = 1\,\mathrm{mA}$, $R_C = 500\,\Omega$, $U_{0C} = 10\,\mathrm V$

\bigskip

$U_{BA} = U_{EA} + U_{BE0} \approx I_{CA} \cdot R_E + U_{BE0} = 1{,}1\,\mathrm
V$

\bigskip

muss mit dem "`Spannungsteiler"' $R_1$/$R_2$ eingestellt werden.

\end{minipage}%

\smallskip

\paragraph{Annahme:} Um den Spannungsteiler m"oglichst wenig zu belasten, wird
$I_{R_1} = \alpha \cdot I_{BA}$ mit $\alpha = 10$ gew"ahlt.

\[R_1 = \frac{U_{BA}}{\alpha \cdot I_{BA}} = 11\,\mathrm k\Omega \qquad R_2 =
\frac{U_{0C} - U_{BA}}{(1+\alpha)\cdot I_{BA}} = 81\,\mathrm k\Omega\]
\subsubsection*{Nachrechnen des Spannungsteilerverh"altnisses}
\[\frac{R_1}{R_1 + R_2} = \frac{11\,\mathrm k\Omega }{11\,\mathrm k\Omega  +
81\,\mathrm k\Omega} \qquad \frac{U_{BA}}{U_{0C}} = \frac{1{,}1\,\mathrm
V}{10\,\mathrm V} = 0{,}11\]

\smallskip

Relative "Anderung: \ 9\%.

\subsubsection*{Nachrechnen des Eingangsleitwertes}
\[g_e = \frac 1 {R_1} + \frac 1 {R_2} + \frac{1}{r_{BE}} =
\underbrace{0{,}09\,\mathrm{mS} + 0{,}12\,\mathrm{mS}}_{9{,}7\,\mathrm k\Omega}
+ \underbrace{0{,}38\,\mathrm{mS}}_{2{,}6\,\mathrm k\Omega}\]
Relative "Anderung: \ $g_e:$ 27\% $\uparrow$, $r_e:$ 21\% $\downarrow$

\subsubsection*{Arbeitspunkteinstellung bei Sourcestufen}

\begin{minipage}{6cm}
\center
\begin{picture}(120,130)
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\end{picture}
\end{minipage}%
\hfill Enhancement FET \hfill
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\center
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\thicklines
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\qbezier(30,15)(30,15)(45,15)
\end{picture}
\end{minipage}

\bigskip
\bigskip

\begin{minipage}{6cm}
\center
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\hfill Depletion FET, R"ohre \hfill
\begin{minipage}{6cm}
\center
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\put(83,28){\makebox(0,0)[l]{$I_{DA}$}}
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\put(67,7){\makebox(0,0){$U_{GSA}$}}
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\multiput(81,28)(-4,0){4}{\line(-1,0){2}}
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\put(45,14){\line(0,1){2}}
\thicklines
\qbezier(45,15)(80,28)(115,95)
\qbezier(30,15)(30,15)(45,15)
\thinlines
\put(80,15){\line(-1,1){30}}
\put(48,50){\makebox(0,0)[b]{$I_{D} = \frac{U_{DS}}{R_S}$}}
\end{picture}
\end{minipage}%

\subsection{Emitterschaltung mit Laststromquelle}

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\subsubsection*{Kleinsignal-Ersatzschaltbild}

\smallskip

\begin{center}
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\put(48,30){\makebox(0,0)[r]{$r_{BE}$}}

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\put(90,30){\makebox(0,0)[l]{$\Big\downarrow g_{m1}u_e$}}

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\end{picture}
\end{center}

\begin{description}
\item[Leerlaufverst"arkung:] $v = \left.\dfrac{u_a}{u_e}\right|_{i_a=0} =
-g_{m1}(r_{CE1}\parallel r_{CE1})$
\item[Beispiel:]
$I_0 = I_{C1/2A} = I_{CA} = 200\mu\mathrm A$. $U_{Y1/2} = 100\,\mathrm
V$, $U_{CE1/2A} = U_{CE} = 5\,\mathrm V$, $U_T = 26\,\mathrm{mV}$
\begin{align*}
v =& -g_{m1} \cdot (r_{CE1}\parallel r_{CE1}) =  -g_{m1} \cdot \frac{r_{CE}}{2}
= - \frac{I_{CA}}{U_T} \cdot \frac{U_Y + U_{CEA}}{2\cdot I{CA}}\\
&= - \frac{U_Y + U_{CEA}}{2\cdot U_T}
\end{align*}
\end{description}


\section{Basisschaltung und Gateschaltung}
\subsection{Gro"ssignalverhalten}
\begin{minipage}{8cm}
\center

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\put(70,35){\makebox(0,0)[b]{$I_C$}}

\end{picture}

\end{minipage}%
\begin{minipage}{8cm}
\center

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\end{picture}



\end{minipage}%


\begin{minipage}{8cm}
\begin{align*}
I_C &= I_S \cdot e^{\frac{U_{BE}}{U_T}}\\[1ex]
U_{BE} &= - U_e \\[1ex]
U_a &= U_{0C} - I_C \cdot R_C\\
&= U_{0C} - R_C \cdot I_S \cdot e^{\frac{U_{BE}}{U_T}}
\end{align*}
\end{minipage}%
\begin{minipage}{8cm}
\begin{align*}
I_D &= k (U_{GS} - U_t)^2 \\[1ex]
U_{GS} &= -U_e\\[1ex]
U_a &= U_{0D} - I_D \cdot R_D \\ 
&= U_{0D} - R_D \cdot k (U_{GS} - U_t)^2
\end{align*}
\end{minipage}%

\subsubsection*{Transferkennlinien}

\begin{minipage}{8cm}
\center
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\end{picture}
\end{minipage}%
\begin{minipage}{8cm}
\center
\begin{picture}(150,100)
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\put(0,30){\vector(1,0){150}}
\put(140,23){\makebox(0,0)[c]{$U_e$}}
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\end{picture}
\end{minipage}%

\subsubsection*{Kleinsignalverst"arkung}

\begin{minipage}{8cm}
\begin{align*}
v &= \frac{I_S \cdot  R_C}{U_T} \cdot e^{-\frac{U_{BA}}{U_T}} =
\frac{I_{CA}}{U_T} \cdot R_C
= g_m \cdot R_C
\end{align*}
\end{minipage}%
\begin{minipage}{8cm}
\begin{align*}
v = g_m \cdot R_D = 2R_D \sqrt{k\cdot I_{DA}} \vphantom{\frac{I}{U_T}}
\end{align*}
\end{minipage}%

\subsubsection*{Eingangskennlinien}

\begin{minipage}{8cm}
\[I_e = -I_E = -I_S \cdot \frac{B_F + 1}{B_F}\cdot e^{-\frac{U_e}{U_T}}\]
\end{minipage}%
\begin{minipage}{8cm}
\[I_e = -I_S = -I_D = -k(U_e + U_t)^2\]
\end{minipage}%

\begin{minipage}{8cm}
\center
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\qbezier(40,10)(50,90)(90,90)
\end{picture}

\end{minipage}%
\begin{minipage}{8cm}
\center
\begin{picture}(120,120)
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\put(0,90){\vector(1,0){120}}
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\put(75,93){\makebox(0,0)[b]{$-U_t$}}
\end{picture}

\end{minipage}%

\newpage

\paragraph{Eingangsleitwert:} $g_e =
\left.\frac{dI_e}{dU_e}\right|_{\mathrm{AP}} = \frac{1}{r_e}$

\begin{minipage}{8cm}
\[
g_e = \frac{B_F + 1}{B_F} \cdot \frac{I_S \cdot e^{-\frac{U_e}{U_T}}}{U_T} =
 = \underbrace{\frac{B_F + 1}{B_F}}_{\approx 1} \cdot
\underbrace{\frac{I_{CA}}{U_T}}_{g_m}
\]
\end{minipage}%
\begin{minipage}{8cm}
\[
g_e = 2k(U_e + U_t) = 2\sqrt{k I_{DA}} = g_m
\]
\end{minipage}%

\subsection{Kleinsignalverhalten}
\begin{center}
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\end{center}

\begin{minipage}{8cm}
\center 
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\end{picture}
\end{minipage}%
\begin{minipage}{8cm}
\center
\begin{align*}
u_G^* &= U_G \cdot \frac{R_E}{R_E+R_G} &  g_CE &= \frac 1 {r_{CE}}\\
R_L^* &= R_C \parallel R_L &  g_{BE} &= \frac{1}{r_{BE}} \\
R_G^* &= R_E \parallel R_G &  G_L^* &= \frac{1}{R_L^*}
\end{align*}
\end{minipage}%

\subsubsection*{Betriebsparameter}
$\boxed{v_{B1} = \dfrac{u_a}{u_e}}$ \quad KSA:
\textcircled{\raisebox{-1.5pt}{C}}: \quad  $(u_e - u_a) \cdot g_{CE} + g_m
\cdot u_e - G_L^*\cdot u_a = 0$
\[u_a = \frac{g_{CE} + g_m}{g_{CE} + G_L^*}\cdot u_e \quad \Rightarrow \quad
v_{B1} = \frac{g_{CE} + g_m}{g_{CE} + G_L^*} \approx \frac{g_m}{G_L^*}\]

$\boxed{r_{eB} = \dfrac{u_e}{i_e}}$ \quad $g_{eB} = \dfrac{i_e}{u_e}$
\[i_e = g_{BE} \cdot u_e + g_m \cdot u_e - (\underbrace{u_a}_{v_{B1}u_e} - u_e)\cdot g_{CE}
= (g_{BE} + g_m - (v_{B1}-1)g_{CE}) \cdot u_e \]
\[
g_{eB} = g_{BE} + g_m - (v_{B1}-1)g_{CE} = \underbrace{g_{BE}}_{g_m/b} + g_m -
\frac{g_mR^*_L \cancel{-1}}{
g_{CE} R^*_L +1}g_{CE}  \approx g_m \left(1 + \cancel{\frac 1 b} -
\frac{g_mR^*_L }{ g_{CE} R^*_L +1}\right)
\]

\begin{minipage}{8cm}
\[g_e \approx g_m \frac 1 {g_{CE} R_L^* +1}\]

\[\boxed{\quad  r_e = \frac 1 {g_e} = \frac 1 {g_m} \left(1 +
\frac{R_L^*}{r_{CE}}\right) \quad}\]
\end{minipage}%
\begin{minipage}{8cm}
\center
\begin{picture}(170,110)
\put(30,10){\vector(0,1){90}}
\put(25,15){\vector(1,0){140}}
\put(28,93){\makebox(0,0)[r]{$r_e$}}
\put(28,75){\makebox(0,0)[r]{$\frac{2}{g_m}$}}
\put(28,50){\makebox(0,0)[r]{$\frac{1}{g_m}$}}
\put(155,5){\makebox(0,0)[c]{$R_L^*$}}
\put(105,8){\makebox(0,0)[c]{$r_{CE}$}}
\multiput(105,14)(0,4){16}{\line(0,1){2}}
\multiput(29,75)(4,0){19}{\line(1,0){2}}
\put(29,50){\line(1,0){2}}
\put(30,50){\line(3,1){85}}
\put(130,10){\vector(0,1){90}}
\put(133,93){\makebox(0,0)[l]{$r_e/\Omega$}}
\multiput(129,50)(0,25){2}{\line(1,0){2}}
\put(133,50){\makebox(0,0)[l]{20}}
\put(133,75){\makebox(0,0)[l]{40}}

\end{picture}
\end{minipage}%

\newpage
\begin{minipage}{8cm}
$\boxed{r_{aB} = \left.\dfrac{u_a}{i_a}\right|_{U_G=0} }$
\begin{align*}
u_a &= u_e + u_{CE} = u_e + (i_a + g_mu_e)\\
&= (1+g_mr_{CE})u_e + i_a r_{CE}\\[1ex]
u_e &= i_a \cdot r_{BE} \parallel R_G^* = \frac{r_{BE}\cdot R^*_G}{r_{BE}+R^*_G}i_a
\end{align*}
\end{minipage}%
\begin{minipage}{8cm}
\center 
\begin{picture}(200,95)
\put(25,0){\line(1,0){10}}
\put(30,0){\line(0,1){60}}
\multiput(30,60)(40,0){2}{\line(1,0){20}}
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\put(60,67){\makebox(0,0)[b]{$R_G^*$}}
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\multiput(85,20)(0,20){2}{\line(1,0){10}}
\put(85,0){\line(1,0){10}}
\put(97,30){\makebox(0,0)[l]{$r_{BE}$}}
\qbezier(85,55)(75,30)(85,5)
\put(85,5){\vector(1,-3){0}}
\put(77,30){\makebox(0,0)[r]{$u_{e}$}}

\multiput(90,60)(40,0){2}{\line(1,0){20}}
\multiput(110,60)(10,-10){2}{\line(1,1){10}}
\multiput(110,60)(10,10){2}{\line(1,-1){10}}
\put(120,50){\line(0,1){20}}
\put(110,48){\vector(1,0){20}}
\put(120,38){\makebox(0,0)[b]{$g_m u_{e}$}}
\multiput(90,60)(60,0){2}{\circle*2}
\multiput(90,60)(60,0){2}{\line(0,1){20}}
\multiput(90,80)(40,0){2}{\line(1,0){20}}
\multiput(110,75)(0,10){2}{\line(1,0){20}}
\multiput(110,75)(20,0){2}{\line(0,1){10}}
\put(120,88){\makebox(0,0)[b]{$r_{CE}$}}
\put(150,30){\circle{20}}
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\put(140,30){\line(1,0){20}}
\put(145,0){\line(1,0){10}}
\put(160,30){\makebox(0,0)[l]{$\Big\uparrow i_a$}}
\qbezier(175,55)(185,30)(175,5)
\put(175,5){\vector(-1,-3){0}}
\put(182,30){\makebox(0,0)[l]{$u_a$}}
\put(80,63){E}
\put(153,63){C}
\put(93,3){B}
\end{picture}

\end{minipage}%


\bigskip

\[r_{aB} = (\cancel 1 + g_m\cdot r_CE) \cdot \frac{r_{BE} R_G^*}{r_{BE}+R_G^*}
+ r_{CE} \approx r_{CE} \left(1 +
b\frac{\frac{R_G^*}{r_{BE}}}{1+\frac{R_G^*}{r_{BE}}}\right)\]

mit $g_m \cdot r_{CE} = \frac{I_{CA}}{U_T}\frac{U_Y}{I_{CA}} = \frac{U_Y}{U_T}
\gg 1$ und $g_m \cdot r_{BE} = \frac{I_{CA}}{U_T} \frac{U_T}{I_B} = B_F \approx
b$.

\bigskip

\begin{minipage}{8cm}
\center
\begin{picture}(200,140)
\setlength{\unitlength}{1.25pt} % groesse flasch eingeschaetzt...
\put(30,10){\vector(0,1){90}}
\put(25,15){\vector(1,0){125}}
\put(28,91){\makebox(0,0)[r]{$\frac{r_{aB}}{r_{CE}}$}}
\put(145,05){\makebox(0,0)[r]{$\frac{R_G^*}{r_{BE}}$}}
\multiput(55,14)(0,4){9}{\line(0,1){2}}
\multiput(29,48)(4,0){7}{\line(1,0){2}}
\put(29,25){\line(1,0){2}}
\multiput(29,70)(4,0){30}{\line(1,0){2}}
\put(27,25){\makebox(0,0)[r]{$1$}}
\put(27,48){\makebox(0,0)[r]{$\scriptstyle (1 + \frac{b}{2})$}}
\put(27,70){\makebox(0,0)[r]{$1 + b$}}
\qbezier(30,25)(60,69)(145,69)
\put(70,45){$r_{aB} > r_{CE}$}
\end{picture}
\end{minipage}%
\begin{minipage}{8cm}
\paragraph{Anwendung:} Stromquelle
\center
\begin{picture}(100,100)
\put(30,0){\line(0,1){60}}
\put(30,30){\circle{20}}
\put(25,0){\line(1,0){10}}
\put(65,0){\line(1,0){10}}
\put(30,60){\line(1,0){30}}
\put(40,60){\line(1,0){20}}
\put(60,50){\thicklines\line(0,1){20}}
\put(60,60){\line(1,1){10}}
\put(60,60){\line(1,-1){10}}
\put(68,52){\vector(1,-1){0}}
\put(70,0){\line(0,1){20}}
\put(70,40){\line(0,1){10}}
\multiput(65,20)(10,0){2}{\line(0,1){20}}
\multiput(65,20)(0,20){2}{\line(1,0){10}}
\put(20,30){\makebox(0,0)[r]{$u_{ref}\Big\downarrow$}}
\put(77,30){\makebox(0,0)[l]{$R_E$}}
\put(70,70){\line(0,1){20}}
\put(70,91){\circle{2}}
\put(74,90){\vector(0,-1){15}}
\put(78,82.5){\makebox(0,0)[l]{$i$}}
\end{picture}
\end{minipage}%

\section{Kollektorstufe (Emitterfolger), Drainstufe (Sourcefolger)}

\subsection{Gro"ssignalverhalten}
\begin{minipage}{5cm}
\begin{picture}(100,120)
\put(24,0){\line(1,0){10}}
\put(65,0){\line(1,0){10}}
\put(30,70){\line(1,0){30}}
\put(40,70){\line(1,0){20}}
\put(60,60){\thicklines\line(0,1){20}}
\put(60,70){\line(1,1){10}}
\put(60,70){\line(1,-1){10}}
\put(68,62){\vector(1,-1){0}}
\put(70,0){\line(0,1){15}}
\put(70,35){\line(0,1){25}}
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\multiput(65,15)(0,20){2}{\line(1,0){10}}
\put(28,35){\makebox(0,0)[r]{$U_{e}$}}
\put(29,65){\vector(0,-1){60}}
\put(29,70){\circle2}
\put(63,25){\makebox(0,0)[r]{$R_E$}}
\put(85,25){\makebox(0,0)[l]{$U_a$}}
\put(70,80){\line(0,1){20}}
\put(70,101){\circle{2}}
\put(70,105){\makebox(0,0)[b]{$U_{0C}$}}
\qbezier(50,65)(50,55)(65,55)
\put(65,55){\vector(1,0){0}}
\put(58,55){\makebox(0,0)[tr]{$U_{BE}$}}
\qbezier(80,12.5)(85,22.5)(80,37.5)
\put(80,12.5){\vector(-1,-3){0}}
\put(75,60){\vector(0,-1){15}}
\put(78,52.5){\makebox(0,0)[l]{$I_E$}}
\end{picture}
\end{minipage}%
\begin{minipage}{11cm}
\paragraph{Transferkennlinie:} $U_a = f(U_e)$
\[U_a = R_E \cdot I_E = R_E (I_C + I_B) = \frac{B+1}{B} \cdot  I_C \cdot R_E\]
\[I_C = I_S \cdot e^{\frac{U_{BE}}{U_T}}, \quad U_{BE} = U_e - U_a\]
\[U_a = \frac{B+1}{B} \cdot  I_S \cdot  R_E \cdot  e^{\frac{U_e-U_a}{U_T}}\]
kann nicht nach $U_a$ aber nach $U_e$ aufgel"ost werden.
\end{minipage}%

\bigskip
\bigskip

\begin{minipage}{10cm}
\[\Rightarrow \quad U_e = U_a + \underbrace{U_T \mathop\mathrm{ln}\,\frac{U_a}{\frac{B+1}{B}R_E I_s}}_{
U_{BE}} \qquad\]
\begin{description}
\item[Beispiel:] $U_a = 1\ldots 10\,\mathrm V$, $R_E = 1\,\mathrm k\Omega$,
$I_S = 100\,\mathrm{pA}$  

$\Rightarrow U_{BE} = 0{,}48\mathrm V \ldots 0{,}55 \mathrm V \to U_e \approx
U_a + \underbrace{U_{BE0}}_{0{,}5\,\mathrm V}$ 
\end{description}
\end{minipage}%
\begin{minipage}{6cm}
\begin{picture}(130,100)
\put(20,10){\vector(0,1){90}}
\put(15,15){\vector(1,0){115}}
\put(18,90){\makebox(0,0)[r]{$U_a$}}
\put(125,8){\makebox(0,0)[r]{$U_e$}}
\put(20,15){\line(1,1){70}}
\thicklines
\qbezier(20,15)(35,20)(45,30)
\qbezier(45,30)(45,30)(95,80)
\end{picture}
\end{minipage}%

\bigskip

$\Rightarrow$ Die Ausgangsspannung folgt der Eingangsspannung im Abstand von
$U_{BE0}$

\subsubsection*{Verst"arkung:}
\begin{minipage}{9cm}
 \[ \frac
1 v = \left.\frac{dU_e}{dU_a}\right|_A = 1 + \frac{U_T}{U_aA}, \quad v =
\frac{1}{1+\frac{U_T}{U_{aA}}} \approx 1 - \frac{U_T}{U_{aA}}\]
\end{minipage}%
\begin{minipage}{7cm}
\center
\begin{tabular}{c|c|c|c}
$\frac{U_{aA}}{v}$ & 1 & 5 & 10 \\
\hline
$1-v$  & 0{,}03 & 0{,}006 & 0{,}0003
\end{tabular}
\end{minipage}%

\bigskip

$\Rightarrow$ \textbf{Transferkennlinie} $\to$ Gerade, $v \approx 1$

\subsubsection*{Signalverarbeitungsstruktur}

\begin{center}
\begin{picture}(260,60)
\put(0,40){\vector(1,0){20}}
\put(25,40){\circle{10}}
\put(30,40){\vector(1,0){30}}
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\qbezier(85,55)(95,55)(100,40)
\put(80,40){\makebox(0,0){$\scriptstyle I_S\cdot e^{\frac{U_{BE}}{U_T}}$}}
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\multiput(130,25)(30,0){2}{\line(0,1){30}}
\put(145,40){\makebox(0,0){$\frac{B+1}{B}$}}
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\multiput(190,25)(30,0){2}{\line(0,1){30}}
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\put(25,5){\line(1,0){215}}
\put(25,5){\vector(0,1){30}}
\put(10,45){\makebox(0,0)[b]{$U_e$}}
\put(45,45){\makebox(0,0)[b]{$U_{BE}$}}
\put(115,45){\makebox(0,0)[b]{$I_{C}$}}
\put(175,45){\makebox(0,0)[b]{$I_{E}$}}
\put(250,45){\makebox(0,0)[b]{$U_{a}$}}
\put(20,30){\makebox(0,0)[r]{$-$}}
\end{picture}
\end{center}

\subsection{Kleinsignalverhalten}

\begin{minipage}{7cm}
\center
\begin{picture}(190,125)
\put(30,0){\line(0,1){60}}
\put(30,30){\circle{20}}
\put(20,30){\makebox(0,0)[r]{$U_G\Big\downarrow$}}
\put(30,60){\line(1,0){10}}
\put(70,56){\vector(0,-1){56}}
\put(68,30){\makebox(0,0)[r]{$u_e$}}

\multiput(40,55)(0,10){2}{\line(1,0){20}}
\multiput(40,55)(20,0){2}{\line(0,1){10}}
\put(50,68){\makebox(0,0)[b]{$R_G$}}
\multiput(60,60)(22,0){2}{\line(1,0){18}}
\multiput(78,53)(4,0){2}{\thicklines\line(0,1){14}}
\multiput(100,60)(0,40){2}{\line(0,1){20}} %RB
\multiput(95,80)(10,0){2}{\line(0,1){20}}
\multiput(95,80)(0,20){2}{\line(1,0){10}}
\put(100,60){\circle*2}
\put(100,60){\line(1,0){20}}
\put(120,50){\thicklines\line(0,1){20}}
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\put(120,60){\line(1,-1){10}}
\put(128,52){\vector(1,-1){0}}
\put(130,70){\line(0,1){50}}

\put(130,00){\line(0,1){20}}
\put(130,40){\line(0,1){10}}
\multiput(125,20)(10,0){2}{\line(0,1){20}}
\multiput(125,20)(0,20){2}{\line(1,0){10}}

\put(125,00){\line(1,0){10}}
\put(25,00){\line(1,0){10}}
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\put(170,0){\line(0,1){20}}
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\multiput(165,20)(0,20){2}{\line(1,0){10}}
\put(170,40){\line(0,1){10}}
\put(165,0){\line(1,0){10}}
\put(100,120){\line(1,0){50}}
\put(151,120){\circle{2}}
\multiput(130,50)(0,70){2}{\circle*{2}}
\put(155,120){\makebox(0,0)[l]{$U_{0C}$}}
\put(093,90){\makebox(0,0)[r]{$R_{2}$}}
\put(163,30){\makebox(0,0)[r]{$R_{L}$}}
\put(70,60){\color{white}\circle*{2}}  % *hust*
\put(70,60){\circle{2}}                % *kotz*
\multiput(100,0)(0,40){2}{\line(0,1){20}}
\multiput(95,20)(10,0){2}{\line(0,1){20}}
\multiput(95,20)(0,20){2}{\line(1,0){10}}
\put(95,0){\line(1,0){10}}
\put(094,30){\makebox(0,0)[r]{$R_{1}$}}
\put(124,30){\makebox(0,0)[r]{$R_{E}$}}
\qbezier(175,50)(185,30)(175,10)
\put(175,10){\vector(-1,-3){0}}
\put(182,30){\makebox(0,0)[l]{$u_{a}$}}
\end{picture}
\end{minipage}%
\begin{minipage}{9cm}

\begin{picture}(200,80)
\put(30,0){\line(0,1){60}}
\put(30,30){\circle{20}}
\put(25,0){\line(1,0){10}}
\put(20,30){\makebox(0,0)[r]{$U_G^*\Big\downarrow$}}
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\multiput(45,55)(20,0){2}{\line(0,1){10}}
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\put(81,60){\circle2}
\put(81,68){\makebox(0,0)[b]{B}}
\put(120,5){\makebox(0,0)[b]{C}}
\put(132,68){\makebox(0,0)[b]{E}}
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\multiput(97,55)(20,0){2}{\line(0,1){10}}
\put(107,68){\makebox(0,0)[b]{$r_{BE}$}}
\multiput(132,0)(0,40){2}{\line(0,1){20}}
\multiput(132,20)(-10,10){2}{\line(1,1){10}}
\multiput(132,20)(10,10){2}{\line(-1,1){10}}
\put(122,30){\line(1,0){20}}
\put(124,30){\makebox(0,0)[r]{$g_mu_{BE}\!\Big\uparrow $}}
\put(81,56){\vector(0,-1){56}}
\put(80,30){\makebox(0,0)[r]{$u_e$}}
\put(127,0){\line(1,0){10}}
\put(132,60){\circle*2}
\put(132,60){\line(1,0){88}}

\multiput(10,0)(30,0){3}{
\multiput(150,0)(0,40){2}{\line(0,1){20}}
\multiput(145,20)(10,0){2}{\line(0,1){20}}
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\put(145,0){\line(1,0){10}}
}
\put(160,60){\circle*{2}}
\put(190,60){\circle*{2}}

\put(166,30){\makebox(0,0)[l]{$r_{CE}$}}
\put(196,30){\makebox(0,0)[l]{$R_{E}$}}
\put(226,30){\makebox(0,0)[l]{$R_{L}$}}

\qbezier(237.5,5)(247.5,30)(237.5,55)
\put(237.5,5){\vector(-1,-3){0}}
\put(245,30){\makebox(0,0)[l]{$u_a$}}
\put(190,75){\makebox(0,0){$\overbrace{\hspace{2.5cm}}^{\displaystyle R_L^*}$}}
\end{picture}

\end{minipage}%

\bigskip
\bigskip

\[U_G^* = \frac{R_1\parallel R_2}{R_G + R_1\parallel R_2} U_G, \quad R_G^* =
R_1\parallel R_2 \parallel R_G, \quad R_L^* = r_{CE}\parallel R_L \parallel R_E\]

\subsubsection*{Signalflu"sgraph}

\begin{minipage}{8cm}
\center
\begin{picture}(200,75)
\put(0,-15){  % verschaetzt, oben links angefangen :)
\put(26,60){\makebox(0,0)[r]{$u_e$}}
\put(30,60){\circle*3}
\put(30,60){\vector(1,0){22}}
\put(50,64){\makebox(0,0)[b]{$1$}}
\put(30,60){\line(1,0){40}}
\put(70,60){\circle*3}
\put(70,66){\makebox(0,0)[b]{$u_{BE}$}}
\qbezier(70,60)(80,70)(110,70)
\put(93,69){\vector(4,1){0}}
\put(90,73){\makebox(0,0)[b]{$\frac{1}{r_{BE}}$}}
\put(110,70){\circle*3}
\put(110,74){\makebox(0,0)[b]{$i_{e}$}}
\qbezier(110,70)(140,70)(150,60)
\put(132,68){\vector(4,-1){0}}
\put(132,73){\makebox(0,0)[b]{$1$}}
\put(150,60){\circle*3}
\put(150,64){\makebox(0,0)[b]{$i_{E}$}}
\put(150,60){\line(1,0){40}}
\put(150,60){\vector(1,0){22}}
\put(170,64){\makebox(0,0)[b]{$R_{L}^*$}}
\put(190,60){\circle*3}
\put(194,60){\makebox(0,0)[l]{$u_{a}$}}

\qbezier(70,60)(80,50)(110,50)
\put(93,51){\vector(4,-1){0}}
\put(90,47){\makebox(0,0)[t]{${g_{m}}$}}
\put(110,50){\circle*3}
\put(110,46){\makebox(0,0)[t]{$i_{C}$}}
\qbezier(110,50)(140,50)(150,60)
\put(132,52){\vector(4,1){0}}
\put(132,47){\makebox(0,0)[t]{$1$}}

\qbezier(70,60)(80,25)(130,25)
\qbezier(130,25)(180,25)(190,60)
\put(128,25){\vector(-1,0){0}}
\put(130,22){\makebox(0,0)[t]{$-1$}}
}
\end{picture}
\end{minipage}%
\begin{minipage}{8cm}
\center
\begin{align*}
u_{BE} &= u_e - u_a  &
i_e &= \frac{u_e}{r_{BE}} = i_B \\[1ex]
i_E & = i_e + i_C & 
u_a & = R_L^* \cdot i_E 
\end{align*}
\end{minipage}%

\subsubsection*{Verst"arkung}
\[v_{B1} = \frac{u_a}{u_e} = \frac{\left(g_m + \frac 1{r_BE}\right)R^*_L}{1+
\left(g_m + \frac 1{r_BE}\right)R^*_L} = \frac{\left(1 + \frac 1 b\right) g_m
R_L^*}{1+ \left(1 + \frac 1 b\right) g_m R_L^*} \approx
\frac{g_mR_L^*}{1+g_mR^*_L} \approx 1\]
\subsubsection*{Eingangswiderstand}
\[g_{eB} = \frac{i_e}{u_e} = \frac{\frac 1{r_BE}}{1+\left(\frac 1{r_BE} +
g_m\right)R^*_L}, \quad r_{eB} = \frac{1}{g_{eB}} = r_{BE} + (1 +
\overbrace{g_mr_{BE}}^{b}) R_L^* \approx r_{BE} + b \cdot r_L^* \]
\subsubsection*{Ausgangswiderstand}
\begin{minipage}{3cm}
\center
\[r_{aB} = \left.\frac{u_a}{i_a}\right|_{U_G^*=0}\]
\end{minipage}%
\begin{minipage}{6cm}
\center
\begin{picture}(130,60)
\put(2,45){\makebox(0,0)[l]{$i_a$}}
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\put(95,26){\makebox(0,0)[tl]{$\frac{-r_{BE}}{R_G^*+r_{BE}}$}}
\end{picture}
\end{minipage}%
\begin{minipage}{7cm}
\[u_a = i_1 (R_G^*+r_{BE}) \qquad i_1 = g_mu_{BE} + i_a\]
\[u_{BE} = - \frac{r_{BE}}{R_G^*+r_{BE}}u_a, \qquad i_1 = -i_e\]
\end{minipage}%

\bigskip
\bigskip

\[r_{aB} = \frac{R_G^* + r_{BE}}{11 + r_{BE} g_m} = \frac{R_G^* + r_{BE}}{1+b}
\approx \frac 1 {g_m} + \frac{R_G^*}{b}\]

\section{Stromspiegel}
\subsection{Grundmodell}

\begin{minipage}{5cm}
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\end{picture}
\end{minipage}%
\begin{minipage}{11cm}
\[I_2 = M \cdot I_1 \qquad M: \text{ Spiegelverh"altnis, ganzzahlig}\]
\begin{minipage}{0.5\textwidth}
\begin{empheq}[innerbox=\fbox]{align*}
\quad U_1 &= H_1 (I_1,\,U_2) \quad\\
\quad I_2 &= H_2 (I_1,\, U_2) 
\end{empheq}
\end{minipage}%
\begin{minipage}{0.5\textwidth}
Hybriddarstellung
\end{minipage}%
\end{minipage}%

\subsubsection*{Kleinsignalmodell}
\begin{minipage}{8cm}
\center
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\end{picture}
\end{minipage}%
\begin{minipage}{8cm}
\begin{align*}
u_1 &= r_e \cdot i_1 + \nu \cdot u_2\\
i_2 &= m \cdot  i_1 + g_a \cdot u_2
\end{align*}
\vspace{-1.2cm}
\[\underbrace{\hphantom{\ i_2 = m \cdot  i_1\ }}_{\displaystyle\text{Hauptsteuergleichung}}
\hphantom{+ g_a \cdot u_2}\]
\end{minipage}%

\subsection{Grundschaltung}

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\center
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\end{picture}
\end{minipage}%
\begin{minipage}{9cm}
\[I_B = \frac{I_S}{B_F}\cdot e^{\frac{U_{BE}}{U_T}}, \quad I_{C1/2} = I_S \cdot
e^{\frac{U_{BE}}{U_T}}\left(1+\frac{U_{1/2}}{U_Y}\right) \]

\[I_1 = I_{C1} + 2I_B = I_S \cdot e^{\frac{U_{BE}}{U_T}}\left(1+ 
\frac{U_{1}}{U_Y} + \frac 2 {B_F}\right)\]
\end{minipage}%

\bigskip


\[I_2 = I_{C2} = I_S \cdot
e^{\frac{U_{BE}}{U_T}}\left(1+\frac{U_2}{U_Y}\right) \qquad M =
\frac{I_2}{I_1} \approx \frac{1 +
\frac{U_2}{U_Y}}{1+\cancel{\frac{U_{BE0}}{U_Y}}+\frac{2}{B_F}} \approx  \frac{1 +
\frac{U_2}{U_Y}}{1+\frac{2}{B_F}}  \]

\subsection{Verbesserung der Symmetrie (Bipolar-Stromspiegel)}

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\center
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\end{minipage}%
\begin{minipage}{9cm}
\[B_1 = B_2 = B, \quad I_{B1} = I_{B2}\]

\[M = \frac{I_2}{I_1} = \frac{1}{1+\frac{2}{B(1+B_3)}} \approx 1 -
\frac{2}{B(1+B_3)}\]
\end{minipage}%

\bigskip

\paragraph{Zahlenbeispiel:} $B_1 = B_2 = 100$, $B_3 = 50$, $M = 1-0{,}4\cdot
10^{-3}$

\subsection{Strombank}

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\subsection{Verbesserung des Ausgangsverhaltens (Wilson-Stromspiegel)}

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\bigskip

Alle Transistoren f"uhren den gleichen Arbeitspunkt-Strom. $g_{m1} = g_{m2} =
g_{m3} = g_m$

\begin{align*}
\text{\textcircled{\raisebox{-1.5pt}{1}}} &&  i_1 - g_{DS1}\cdot u_1 - g_m \cdot u_3 &=
0 &&&&&& \\  % baaaaaaaaaaaaaaaaaaaaah
\text{\textcircled{\raisebox{-1.5pt}{2}}} && i_2 - g_{DS3}(u_2-u_3) - g_m(u_1-u_3) &=
0\\
\text{\textcircled{\raisebox{-1.5pt}{3}}} && i_2 - g_{DS2}\cdot u_3 - g_m\cdot u_3 &=0
\end{align*}
\textbf{gegeben:} $u_2$, $i_1$ \qquad \textbf{gesucht:} $i_2$, ($u_1$, $u_3$
ebenso unbekannt)
\[i_2 =
\underbrace{\frac{g_m}{g_{DS1}\left(2+\frac{g_m}{g_{DS1}}\right)}}_{\displaystyle m}
\cdot i_1 + \underbrace{\frac{g_{DS3}}{1+\frac{g_m}{g_{DS1}}}}_{\displaystyle
g_a}\cdot u_2 \qquad 
\Rightarrow \qquad m \approx 1 \quad (1\text{\textperthousand}), \qquad g_a
\approx \frac{g_{DS3}}{\frac{g_m}{g_{DS1}}} \approx 10^{-1}\,\mathrm S \]

\subsection{Widlar-Stromquelle}

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\qbezier(125,50)(135,30)(125,10)
\put(125,10){\vector(-1,-2){0}}
\put(132,30){\makebox(0,0)[l]{$U_{E2}$}}

\put(160,0){\line(0,1){100}}
\put(155,0){\line(1,0){10}}
\put(160,50){\circle{20}}
\put(170,50){\makebox(0,0)[l]{$\Big\downarrow U_{2}$}}
\put(125,89){\makebox(0,0)[l]{$\Big\downarrow I_{2}$}}
\end{picture}
\end{minipage}%
\begin{minipage}{8cm}
\[I_1 \approx I_S \cdot e^{\frac{U_{BE1}}{U_T}} \qquad I_2 = I_S\cdot
e^{\frac{U_{BE2}}{U_T}}\]
\[U_{BE2} = U_{BE1} - U_{E2} \approx U_{BE1} -  I_2\cdot R_E\]
\[I_2 = I_S \cdot e^{\frac{U_{BE1}- I_2R_E }{U_T}} = \underbrace{I_S\cdot
e^{\frac{U_{BE1}}{U_T}}}_{I_1} \cdot e^{\frac{-I_2R_E}{U_T}} \]
\[\boxed{\quad I_2 = I_1 \cdot e^{\frac{-I_2R_E}{U_T}}\quad
\vphantom{\int_a^a}}\]
\end{minipage}%

% Trivialgraphik I2/I1 mit veraenderlichem R_E gespart

\subsubsection*{Ausgangswiderstand}

\begin{minipage}{4cm}
\center
\begin{picture}(100,75)
\put(15,0){\line(1,0){10}}
\put(20,0){\line(0,1){60}}
\put(20,30){\circle{20}}
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\multiput(40,55)(20,0){2}{\line(0,1){10}}
\put(50,68){\makebox(0,0)[b]{$g_a$}}
\put(81,60){\circle{2}}
\put(81,55){\vector(0,-1){55}}
\put(83,30){\makebox(0,0)[l]{$u_{BE1}$}}
\put(92.5,63){\makebox(0,0)[b]{$i_{B1}$}}
\put(100,60){\vector(-1,0){15}}
\end{picture}
\end{minipage}%
\begin{minipage}{6cm}
\hfill
\begin{picture}(130,75)
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\multiput(30,20)(-10,10){2}{\line(1,1){10}}
\multiput(30,20)(10,10){2}{\line(-1,1){10}}
\put(20,30){\line(1,0){20}}
\put(20,30){\makebox(0,0)[r]{$g_a u_{BE1}\Big\downarrow$}}
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\put(50,0){\line(1,0){10}}
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\put(55,60){\circle*2}
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\put(91,60){\circle2}
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\put(93,30){\makebox(0,0)[l]{$u_{BE1}$}}
\put(63,30){\makebox(0,0)[l]{$r_{BE}$}}
\end{picture}
\end{minipage}%
\begin{minipage}{5cm}
\[i_{B1} = g_mu_{BE1} + \frac{u_{BE1}}{r_{BE}} \]
\[\to \quad g_a = g_m + \frac 1 {r_{BE}}\]
\end{minipage}%

\bigskip

$\to$ Transistor 2 in Basisschaltung
\[r_a  = (1 + g_{m2} R_E) \cdot r_{CE2} \approx g_m \cdot r_{CE2} \cdot R_{E} =
\frac{U_Y}{U_T}\cdot R_E\]

\paragraph{Bemessungsbeispiel:} gegeben: $I_1 = 1\,\mathrm{mA}$, $I_2 =
200\,\mu\mathrm A$, $U_Y = 100\,\mathrm V$,
gesucht: $R_E$, $r_a$
\[R_E = \frac{U_T}{I_2}\ln\frac{I_1}{I_2} =
\frac{25\,\mathrm{mV}}{200\,\mu\mathrm A} \cdot \ln
\frac{1\,\mathrm{mA}}{200\,\mu\mathrm A} = 201\,\Omega, \qquad
r_a = \frac{U_Y}{U_T}\cdot R_E = 805\,\mathrm k\Omega\]

\section{Differenzstufe}
\subsection{Gro"ssignalverhalten}
\begin{minipage}{8cm}
\center
\begin{picture}(155,110)
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\put(27,35){\makebox(0,0)[r]{$U_{e1}$}}
\put(135,35){\makebox(0,0)[l]{$U_{e2}$}}
\put(90,30){\makebox(0,0)[l]{$\Big\downarrow I_{E}$}}
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\put(62,30){\makebox(0,0)[r]{$U_{E}$}}
\end{picture}
\end{minipage}%
\begin{minipage}{8cm}
\begin{description}
\item[gesucht:] $I_{C1}$ und $I_{C2}$ un Abh"angigkeit von $U_{e1}$ und
$U_{e2}$.
\item[Transistormodell:]
\[I_C = I_S \cdot e^{\frac{U_{BE}}{U_T}}\]
\[I_B = \frac{I_C}{B_F}\]
\end{description}
\end{minipage}%

\bigskip

\bigskip

\[I_{C1} = I_S \cdot e^{\frac{U_{e1} - U_E}{U_T}}, \qquad I_{C2} = I_S \cdot
e^{\frac{U_{e2} - U_E}{U_T}}, \qquad (I_{C1} - I_{C2}) \cdot \underbrace{(1 +
\scriptstyle \frac 1 B\displaystyle)}_{\approx 1} = I_E \]

\[\begin{array}{rlclll}
I_{C1} - I_{C2}  &=& I_S \cdot \left( e^{\frac{U_{e1} - U_E}{U_T}}-
e^{\frac{U_{e2} - U_E}{U_T}}\right) &= I_S \cdot
e^{-\frac{U_E}{U_T}}\left(e^{\frac{U_{e1}}{U_T}} - e^{\frac{U_{e2}}{U_T}}\right)
\\[2ex]
I_E = I_{C1} + I_{C2} &=& \cdots  &=I_S \cdot e^{\frac{- U_E}{U_T}}
\left(e^{\frac{U_{e1}}{U_T}} + e^{\frac{U_{e2}}{U_T}}\right)
\end{array}\]
\[\Rightarrow I_{C1} - I_{C2} = I_E \cdot \frac{e^{\frac{U_{e1}}{U_T}} -
e^{\frac{U_{e2}}{U_T}}}{e^{\frac{U_{e1}}{U_T}} + e^{\frac{U_{e2}}{U_T}}} = I_E
\cdot \tanh \frac{U_{e1}-U_{e2}}{2U_T} \]
\paragraph{Definitionen:} $I_{ad} = I_{C1} - I_{C2}$, $U_{ed} = U_{e1} -
U_{e2}$
\[\Rightarrow \quad \boxed{\quad I_{ad} = I_E \cdot \tanh \frac{U_{ed}}{2U_T}  \quad}\]
$\left.\begin{array}{ll}
I_{C1} - I_{C2} &= I_{ad}\\
I_{C1} + I_{C2} &= I_{E}
\end{array}\right\}
\quad I_{C1} = \frac{I_{ad} + I_E}{2} = \frac{I_E}{2}\left(1 +
\tanh\frac{U_{ed}}{2U_T}\right), \ 
 I_{C2} = \frac{I_E - I_{ad}}{2} = \frac{I_E}{2}\left(1 -
\tanh\frac{U_{ed}}{2U_T}\right)
$

\begin{center}
\begin{picture}(150,150)
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\put(75,0){\vector(0,1){150}}
\qbezier(5,75)(65,75)(75,100)
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\qbezier(145,75)(85,75)(75,100)
\qbezier(5,125)(65,125)(75,100)
\qbezier(5,25)(65,25)(75,75)
\qbezier(75,75)(85,125)(145,125)
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\put(155,79){\makebox(0,0)[b]{$U_{ed}$}}
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\put(145,72){\makebox(0,0)[t]{$\scriptstyle 100\,\mathrm{mV}$}}
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\put(78,145){\makebox(0,0)[l]{$I_{ad}$}}
\multiput(74,125)(4,0){18}{\line(1,0){2}}
\end{picture}
\end{center}

\subsection{Kleinsignalverhalten}
\begin{minipage}{6cm}
\center
\begin{picture}(155,150)
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\put(80,120){\line(0,1){10}}
\put(80,131){\circle2}
\put(80,134){\makebox(0,0)[b]{$U_{0C}$}}

\multiput(55,130)(50,0){2}{\vector(0,-1){15}}
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\put(62,30){\makebox(0,0)[r]{$u_{E}$}}
\end{picture}
\end{minipage}%
\begin{minipage}{10cm}
\center
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\put(200,47){\makebox(0,0)[b]{$r_{BE}$}}
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\put(220,20){\makebox(0,0)[r]{$u_{e2} \Big\downarrow$}}
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\put(130,40){\circle*2}
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\end{picture}
\end{minipage}%

\bigskip

\bigskip

\[u_{a1/2} = -i_{C1/2} \cdot R_C \qquad i_{e1/2} = (u_{e1/2}-u_{E})\cdot g_{BE}
\qquad i_{C1/2} = g_m \cdot (u_{e1/2} - u_E) \]

\[u_E = r_E (i_{E1} + i_{E2}) = \frac{b+1}{b} \cdot r_E (i_{C1} + i_{C2})
\approx r_E (i_{C1} + i_{C2})\]

\subsubsection*{Signalflussplan}

\begin{center}
\begin{picture}(190,120)
\put(27,10){\makebox(0,0)[r]{$u_{e2}$}}
\put(27,110){\makebox(0,0)[r]{$u_{e1}$}}
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\put(77,85){\makebox(0,0)[r]{$-1$}}
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\put(133,85){\makebox(0,0)[l]{$1$}}
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\put(130,7){\makebox(0,0)[t]{$i_{C2}$}}
\put(155,107){\makebox(0,0)[t]{$-R_{C}$}}
\put(155,13){\makebox(0,0)[b]{$-R_{C}$}}
\put(183,10){\makebox(0,0)[l]{$u_{a2}$}}
\put(183,110){\makebox(0,0)[l]{$u_{a1}$}}
\end{picture}
\end{center}

\subsubsection*{Symmetrische Differenzverst"arkung}

\begin{minipage}{6cm}
\center
\begin{picture}(110,50)
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\put(42,10){\makebox(0,0)[l]{$+$}}
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\put(95,40){\makebox(0,0)[l]{$u_{a1}$}}
\end{picture}
\end{minipage}%
\begin{minipage}{10cm}
\begin{align*}
u_{ad} &= u_{a1} - u_{a2} = - g_m R_C (u_{e1} - u_{e2}) = -g_m R_C u_{ed} \\
&= v_{ds} \cdot u_{ed}\\[1ex]
v_{ds} &= -g_m \cdot R_C = \frac{-I_{CA}R_C}{U_T} \approx - \frac{I_E R_C}{2U_T}
\end{align*}
\end{minipage}%

\subsubsection*{Unsymmetrische Differenzverst"arkung}

\begin{minipage}{5cm}
\center
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\put(42,10){\makebox(0,0)[l]{$+$}}
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\put(98.5,25){\circle{2}}
\put(102,25){\makebox(0,0)[l]{$u_{a2}$}}
\end{picture}
\end{minipage}%
\hfill
\begin{minipage}{5cm}
\center
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\put(40,20){\line(1,0){20}}
\put(50,20){\circle{20}}

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\end{minipage}%
\hfill
\begin{minipage}{5cm}
\center
\begin{picture}(100,100)
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\put(0,50){\vector(1,0){100}}
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\put(50,50){\line(-1,1){40}}
\put(48,90){\makebox(0,0)[r]{$u_{e2}$}}
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\put(82,10){\makebox(0,0)[r]{$u_{ed}$}}
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\put(75,78){\makebox(0,0)[b]{$1$}}
\end{picture}
\end{minipage}%

\begin{minipage}{3.5cm}
\center
\[\boxed{u_{ed} = u_{e1} - u_{e2} \vphantom{\dfrac u u}}\]
\end{minipage}%
\begin{minipage}{4.5cm}
\center 

\bigskip

Differenz-
Eingangsspannung
\end{minipage}%
\begin{minipage}{3.5cm}
\center
\[\boxed{u_{egl} = \frac{u_{e1} + u_{e2}}{2}}\]
\end{minipage}%
\begin{minipage}{4.5cm}
\center 

\bigskip

Gleichtakt-Eingangsspannung
\end{minipage}




\begin{minipage}{4cm}
\center
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\end{minipage}%
\hfill
\begin{minipage}{0.5cm}
\center
$\Rightarrow$
\end{minipage}%
\hfill
\begin{minipage}{5cm}
\center
\begin{picture}(120,60)
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\end{minipage}%
\hfill
\hfill
\hfill
\begin{minipage}{5cm}
\center
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\put(117,50){\makebox(0,0)[r]{$u_{ed}$}}
\end{picture}
\end{minipage}%

\subsubsection*{Verst"arkerkenngr"o"sen}

\begin{align*}
u_a & = v_1 \cdot u_{e1} + v_2 \cdot u_{e2} = v_1 \left(u_{egl} +
\frac{u_{ed}}2\right) + v_2 \left(u_{egl} - \frac{u_{ed}}2\right) \\
&= \underbrace{\frac{v_1 - v_2}{2}}_{\displaystyle v_d} \cdot u_{ed} + \underbrace{(v_1 +
v_2)}_{\displaystyle v_{gl}} \cdot u_{egl}\\[3ex]
v_d &= \left.\frac{u_a}{u_{ed}}\right|_{u_{egl}=0} = \frac{v_1-v_2}{2} \qquad
\text{Differenzverst"arkung}\\[2ex]
v_{gl} &= \left.\frac{u_a}{u_{gl}}\right|_{u_{ed}=0} = v_1 + v_2 \qquad\
\text{ Gleichtaktverst"arkung}
\end{align*}
\begin{minipage}{8cm}
\[\boxed{\quad CMRR = 20\,\lg \frac{v_d}{v_{gl}} \, \mathrm{dB}
\vphantom{\frac{d}{d}}  \quad }\]
\end{minipage}%
\begin{minipage}{5.5cm}
\center
Gleichtaktunterdr"uckung

Common Mode Rejection Ratio
\end{minipage}%

\subsubsection*{Berechnung der Kenngr"o"sen}
\[u_{a2} = v_1 \cdot u_{e1} + v_2 \cdot u_{e2} = v_d \cdot u_{ed} + v_{gl}
\cdot u_{egl} \]
Aus Signalflu"sgraph (\textsc{Mason}):
\[u_{a2} = \frac{1}{1+2g_mr_E} \Big({g_m}^2 r_ER_Cu_{e1} -
g_mR_C(1+g_mr_E)u_{e2}\Big)\]
Koeffizientenvergleich:
\[v_1 = \frac{{g_m}^2 r_E R_C}{1+2g_mr_E} \qquad\qquad v_2 = -
\frac{g_mR_C(1+g_mr_E)}{1+2g_mr_E}\]
Differenzverst"arkung:
\[v_d = \frac{v_1 - v_2}{2} = \frac{g_mR_C(g_mr_E + 1 + g_mr_E)}{2(1+2g_mr_E} =
\frac{g_mR_C}{2}\]
Gleichtaktverst"arkung:
\[v_{gl} = v_1 + v_2 = \frac{g_mR_C(g_mr_E-1-g_mr_E)}{1+2g_mr_E} =
\frac{-g_mR_C}{1+2g_mr_E} \approx - \frac{-R_C}{2r_E}\]
Gleichtaktunterdr"uckung:
\[CMMR = 20\log \left|\frac{v_d}{v_{gl}}\right| \approx 20\log (g_m r_E) =
20\log \frac{I_E r_E}{2U_T} \]
Zahlenbeispiel: $I_E = 1\,\mathrm{mA}$, $g_m =
\frac{0{,}5\,\mathrm{mA}}{25\,\mathrm{mV}} = 20\,\mathrm{mS}$, $R_C =
10\,\mathrm k\Omega$

\begin{center}
\begin{tabular}{l|c|c|c}
$r_E/\mathrm k\Omega$ & 1 & 10 & 1000 \\
\hline
$CMRR/\mathrm{dB}$ & 26 & 46 & 86
\end{tabular}
\end{center}

\subsubsection*{Eingangsverhalten}

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\end{picture}
\end{minipage}%
\begin{minipage}{8cm}
$i_{e1}$ aus Signalflu"sgraph:
\[i_{e1} = \frac{g_{BE}}{1+2g_mr_E} \left((1+g_mr_E)u_{e1} - g_mr_Eu_{e2}
\right)\]
$i_{e1}$ aus Ersatzschaltung
\[i_{e1} = (g_{egl} + g_{ed}) u_{e1} - g_{ed} u_{e2}\]
\end{minipage}%

Koeffizientenvergleich:
\[r_{ed} = \frac{1+2g_m r_E}{g_mr_E} \cdot r_{BE}  \approx 2 r_{BE} , \qquad
r_{egl} = r_{BE} \cdot (1+2g_mr_E) \approx 2br_E\]

% gespart: T-ersatzschaltung mit 2* r_BE und b*r_E ; sollte klar sein, wenn man
% keine Flachzange ist.

\paragraph{Anwendung: OTA} (Operational Transconductance Amplifier)

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\end{minipage}%
\begin{minipage}{6cm}
\[i_a = g_m \cdot u_{ed}\]
\end{minipage}%

\bigskip

\begin{minipage}{8cm}
\center
\begin{picture}(190,180)

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\end{picture}
\end{minipage}%
\begin{minipage}{6cm}
\[I_a = I_E \tanh \frac{U_{ed}}{2U_T} \approx \underbrace{\frac{I_E}{2U_T}}
_{g_m} U_{ed}
\]
\end{minipage}%

\chapter{Leistungsverst"arker}

\section{Leistungsbilanz}
[siehe Folie]
\section{A-Verst"arker}
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\begin{minipage}{9.5cm}
\subsubsection*{Annahmen:}
\begin{itemize}
\item symmetrische Aussteuerung \[U_{CEA} = \frac{U_{0C}}{2} =
\widehat{U}_{a,max}, \quad  \widehat{I}_{C,max} = I_{CA}\]
\item $U_{CES}$ und $I_B$ vernachl"assigt
\end{itemize}
\end{minipage}%

\bigskip

\begin{minipage}{6.5cm}
\center
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\put(20,15){\vector(1,0){130}}
\put(23,100){\makebox(0,0)[r]{$I_C$}}
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\put(23,47){\makebox(0,0)[r]{$I_{CA}$}}
\put(140,7){\makebox(0,0)[c]{$U_{CE}$}}
\put(107.5,7){\makebox(0,0)[c]{$U_{0}$}}
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\put(45.625,31){\makebox(0,0)[c]{$P_{TR=}$}}
\put(86.875,31){\makebox(0,0)[c]{$P_{R=}$}}
\end{picture}

\end{minipage}%
\begin{minipage}{9.5cm}
\subsubsection*{Gr"o"senordnungen:}
\[\left.\begin{array}{l@{\ }l} 
U_{0C} &= 20 \ldots 40 \, \mathrm V \\ I_{CA} &= 1 \ldots 10\,\mathrm A
\end{array}\right\} \Rightarrow R = 2 \ldots 40\,\Omega
\]
\end{minipage}%


\subsubsection*{Transistorverlustleistung in Abhängigkeit von $U_{CEA}$}

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\end{minipage}%
\begin{minipage}{8cm}
\[P_{Tr=} = U_{CEA} \cdot I_{CA},\qquad I_{CA} = \frac{U_{0C} - U_{CEA}}{R}\]
\begin{align*}
P_{TR=} &= U_{CEA} \cdot \frac{U_{0C} - U_{CEA}}{R} \\
&= \frac{U_{0C}^2}{R} \cdot \frac{U_{CEA}}{U_{0C}}
\left(1-\frac{U_{CEA}}{U_{0C}}\right)\\
&= P_0 \cdot x(1-x)
\end{align*}
\[P_0 = \frac{{U_{0C}}^2}{R}, \qquad x = \frac{U_{CEA}}{U_{0C}}\]
\end{minipage}%

\begin{minipage}{8cm}
\begin{align*}
I_C(t) &= I_{CA} + \widehat{I}_C \cos \omega t \\
U_a(t) &= U_{aA} + \widehat{U}_a \cos \omega t = U_R 
\end{align*}
\begin{align*}
P_= &= \overline{U_{0C} \cdot I_{C}(t)} = U_{0C} \cdot I_{CA}\\
&= 2 \cdot U_{CEA} \cdot I_{CA} = \frac{{U_{0C}}^2}{2R} = \frac{2{U_{CEA}}^2}{R}
\end{align*}
\end{minipage}%
\begin{minipage}{8cm}
\center
\begin{picture}(175,130)
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%\put(27,120){\makebox(0,0)[r]{$\frac{P_{Tr=}}{P_0}$}}
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\put(30,45){\line(3,2){45}}
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\put(82.5,10){\makebox(0,0)[t]{$\scriptstyle \widehat{U}_{a}$}}
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\put(35,50){\makebox(0,0)[bl]{$\mathbf P_{Tr}$}}
\put(115,50){\makebox(0,0)[br]{$\mathbf P_{R=}$}}
\put(83,90){\makebox(0,0)[l]{$\mathbf P_{S}$}}
\put(57,69.5){\makebox(0,0)[r]{$\scriptstyle\widehat{I}_{a}$}}
\put(67.5,64){\makebox(0,0)[t]{$\scriptstyle\widehat{U}_{a}$}}
\thicklines
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\put(75,75){\line(-3,-2){15}}
\put(60,65){\line(1,0){15}}
\thinlines
\qbezier(67.5,68)(68,90)(80,90)
\end{picture}
\end{minipage}%

 \bigskip

$\displaystyle P_R = P_{R=} + P_S, \qquad P_{R=} = (U_{0C} - U_{CEA})I_{CA} = U_{CEA} \cdot
I_{CA} = \frac{U_{=}}{2}$

\bigskip

$\displaystyle P_S = \frac{\widehat{U}_a \cdot \widehat{I}_a}{2} =
\frac{{\widehat{U}_a}^2}{2R} = \frac{{\widehat{U}_a}^2}{2R} \cdot
\frac{{U_{CEA}}^2}{{U_{CEA}}^2} = \frac{{U_{CEA}}^2}{2R}\cdot m^2 =
\frac{P_=}{4} \cdot m^2$

\bigskip

$\boxed{\quad m = \frac{\widehat U_a}{U_{CEA}} \quad\vphantom{\int^a_a}}$ \qquad
Aussteuerungsgrad \qquad $0 \leq m \leq 1$


\bigskip

$\displaystyle P_{Tr} = P_= - P_R = \overbrace{P_= - P_{R=}}^{P_=/2} - P_S =
P_S\left(\frac 1 2 - \frac{m^2}{4}\right)$


\bigskip


$\eta = \dfrac{P_S}{P_=} = \frac{m^2}{4}$


\begin{minipage}{7cm}
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\put(20,15){\vector(1,0){145}}
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\put(22,55){\makebox(0,0)[r]{$\frac{P_=}2$}}
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\qbezier(25,15)(100,15)(140,35)
\qbezier(25,55)(100,55)(140,75)
\put(140,14){\line(0,1){81}}
\put(143,35){\makebox(0,0)[l]{$\frac{P_=}4$}}
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\put(90,60){\vector(0,-1){45}}
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\put(87,77){\makebox(0,0)[r]{$P_{Tr}$}}
\put(140,12){\makebox(0,0)[t]{$1$}}
\put(160,10){\makebox(0,0)[t]{$m$}}
\end{picture}
\end{minipage}%
\begin{minipage}{9cm}
Mit steigender Aussteuerung nimmt die Transistorverlustleistung ab.


\bigskip

Niedriger Wirkungsgrad ($\leq 25\%$):
\begin{itemize}
\item Gleichleistung an $R$
\item Gleichleistung am Transistor
\end{itemize}
\end{minipage}%


\section{Gegentakt-B- und AB-Verstärker}
\subsection{Leistung und Wirkungsgrad}

\begin{minipage}{5cm}
\centering
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%
\put(30,60){\line(1,0){20}}
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\put(50,60){\line(1,-1){10}}
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\end{picture}
\end{minipage}%
\begin{minipage}{6cm}
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\qbezier(80,53)(110,83)(110,83)
\qbezier(70,50)(65,50)(60,47)
\qbezier(60,47)(30,17)(30,17)
% "sinus"
\qbezier(70,5)(55,7.5)(55,10)
\qbezier(55,10)(55,12.5)(70,15)
\qbezier(70,15)(85,17.5)(85,20)
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\begin{minipage}{5cm}
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\end{picture}
\end{minipage}%

\bigskip

\[U_e(t) = \widehat{U}_e \cdot \cos \omega t, \quad U_a(t) = \widehat{U}_a
\cdot \cos \omega t, \qquad \widehat{U}_a = \widehat{U}_e, \quad \widehat{I}_a
= \widehat{U}_a/R, \quad \widehat{U}_{a,\mathrm{max}} = U_{0C} \]
\subsubsection*{Signalleistung}
$ P_S = \dfrac{{\widehat{U}_a}^2}{2R} = \dfrac{{U_{0C}}^2}{2R}\cdot m^2$,
davon $\frac 1 2 P_S$ oben und  $\frac 1 2 P_S$  unten erzeugt. \qquad
$\boxed{\quad m = \dfrac{\widehat{U}_a}{\vphantom{\widehat{U}_a}U_{0C}} \quad}$


\subsubsection*{Gleichleistung}
\vspace*{-1em}  % :-)
\begin{align*}
P_= &= 2\overline{U_{0C} \cdot I_a(t)} = \underbrace{2}_{\text{\tiny 2
Quellen}} \cdot U_{0C} \cdot \frac{1}{T} \int\limits_0^{T/2} \widehat{I}_a \sin
\omega t\,dt = \frac{2U_{0C}\widehat{I}_a}{2\pi}\int\limits_0^{\pi} \sin u \,
du  
= \frac{2}{\pi} U_{0C} \widehat{I}_a = \frac{2}{\pi} U_{0C}
\frac{\widehat{U}_a}{R}\\ & = \frac{2}{\pi} \frac{{U_{0C}}^2}{R} \cdot m
\end{align*}
davon $\frac 1 2 P_=$ oben und  $\frac 1 2 P_=$  unten erzeugt. 
\subsubsection*{Wirkungsgrad}
$\eta = \frac{P_S}{P_=} = \frac{\pi }{4} \cdot m$, maximal $\frac{\pi}{4}
\approx 0{,}78$
\subsubsection*{Verlustleistung}
Ein Zweig: $\displaystyle P_{Tr} = \frac{P_=}{2} - \frac{P_S}{2} =
\left(\frac{m}{\pi} - \frac{m^2}{4}\right) \frac{{U_{0C}}^2}{R}$

\bigskip

\begin{minipage}{8cm}
\center
\begin{picture}(160,120)
\put(30,10){\vector(0,1){100}}
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\begin{minipage}{8cm}
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\put(90,11){\makebox(0,0)[t]{$\frac{2}{\pi}$}}
\end{picture}
\end{minipage}%


\paragraph{Bemessungsbeispiel:} Leistungsverst"arker $P_S = 20\,\mathrm W$, $R
= 6\,\Omega$

gesucht: $U_{0C}$, $P_{Tr}$

\smallskip

$P_S = \dfrac{{\widehat{U}_a}^2}{2R}, \quad \widehat{U}_{a,\mathrm{max}} =
U_{0C}$

\smallskip

$P_{S,\mathrm{max}} = \dfrac{{U_{0C}}^2}{2R}\quad  \Rightarrow \quad U_{0C} =
\sqrt{2R \cdot P_{max}} = 15{,}5\,\mathrm V \quad \longrightarrow \quad
17\,\mathrm V$ gew"ahlt

\smallskip

$P_{Tr,\mathrm{max}} = \dfrac{1}{\pi^2} \dfrac{{U_{0C}}^2}{R} = \dfrac{1}{\pi^2}
\cdot \dfrac{(17\,\mathrm V)^2}{6\,\Omega} = 4{,}88\,\mathrm W \quad
\longrightarrow \quad 5\,\mathrm W$


\subsection{AB-Betrieb}

\begin{minipage}{8cm}
\centering
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%2
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\qbezier(67,47)(37,17)(37,17)
\end{picture}
\end{minipage}%

\subsubsection*{* $U_{BE}$-Vervielfacher}
\begin{minipage}{5cm}
\centering
\begin{picture}(100,130)
\put(-40,0){
\multiput(70,60)(0,40){2}{\line(0,1){20}} %R2
\multiput(65,80)(10,0){2}{\line(0,1){20}}
\multiput(65,80)(0,20){2}{\line(1,0){10}}
\multiput(70,00)(0,40){2}{\line(0,1){20}} %R1
\multiput(65,20)(10,0){2}{\line(0,1){20}}
\multiput(65,20)(0,20){2}{\line(1,0){10}}
\put(070,60){\circle*2}
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\put(25,15){\line(3,1){80}}
\put(107,40){$R_1+R_2$}
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\end{picture}
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\begin{minipage}{6cm}
\[\frac{R_2}{R_1+R_2} U_g = U_{BE0}\]
\[U_g= \left(1+\frac{R_1}{R_2}\right)\]
\end{minipage}%

\subsection{Strombegrenzung}

Siehe Folie:

\href{http://www.iee.et.tu-dresden.de/iee/ge/student/materialien/ST/folien/leistv/pa1.pdf}{http://www.iee.et.tu-dresden.de/iee/ge/student/materialien/ST/folien/leistv/pa1.pdf}

\chapter{R"uckkopplung}
\section{Grundprinzip}
\subsection{Gro"ssignalverhalten}

\begin{minipage}{8cm}
\centering
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\begin{minipage}{8cm}
\[Y = f(U), \qquad U = X + kY\]
\[\boxed{\quad Y = f(X + kY) = \varphi(X) \vphantom{\int} \quad}\]
i.a. nicht nach $Y$ aufl"osbar.

inverse Beziehung: $X = \varphi^{-1}(Y) = f^{-1}(Y) - kY$
\end{minipage}%


\bigskip
\bigskip

\begin{minipage}{8cm}
\center
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\put(0,60){\vector(1,0){200}}
\put(100,60){\line(1,3){17}}
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\thicklines
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\qbezier(100,60)(90,30)(80,30)
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\thinlines
% k > 0
\qbezier(100,60)(100,90)(110,90)
\qbezier(110,90)(120,90)(120,90)
\qbezier(100,60)(100,30)(90,30)
\qbezier(90,30)(80,30)(80,30)
%k < 0
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\put(117,75){\makebox(0,0)[l]{$k < 0$}}
\put(97,90){\makebox(0,0)[r]{$k > 0$}}
\qbezier(90,85)(90,80)(101.4,80)
\put(97,112){\makebox(0,0)[r]{$Y$}}
\put(190,56){\makebox(0,0)[t]{$X$}}
\end{picture}

\smallskip

$f$ monoton steigend

(nicht invertierender Verst"arker)
\end{minipage}%
\begin{minipage}{8cm}
\center
\begin{picture}(200,120)
\put(100,0){\vector(0,1){120}}
\put(0,60){\vector(1,0){200}}
\put(100,60){\line(1,3){17}}
\put(100,60){\line(-1,-3){17}}
\put(120,115){\makebox(0,0)[l]{$X=kY$}}
\put(17,90){\makebox(0,0)[r]{$f$}}
\thicklines
\qbezier(100,60)(110,30)(120,30)
\qbezier(100,60)(90,90)(80,90)
\qbezier(120,30)(120,30)(180,30)
\qbezier(80,90)(20,90)(20,90)
\thinlines
% k > 0
\qbezier(100,60)(100,30)(110,30)
\qbezier(110,30)(120,30)(120,30)
\qbezier(100,60)(100,90)(90,90)
\qbezier(90,90)(80,90)(80,90)
%k < 0
\qbezier(100,60)(120,30)(130,30)
\qbezier(100,60)(80,90)(70,90)
\put(83,75){\makebox(0,0)[r]{$k > 0$}}
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\put(97,112){\makebox(0,0)[r]{$Y$}}
\put(190,56){\makebox(0,0)[t]{$X$}}

\end{picture}

\smallskip

$f$ monoton fallend

(invertierender Verst"arker)
\end{minipage}%

\paragraph{Beispiel:} Emitterschaltung mit Stromgegenkopplung

\begin{minipage}{6cm}
\center
\begin{picture}(85,110)
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\put(19,45){\vector(0,-1){40}}
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\multiput(45,70)(0,20){2}{\line(1,0){10}}
\put(17,25){\makebox(0,0)[r]{$U_e$}}
\put(43,20){\makebox(0,0)[r]{$R_E$}}
\put(43,80){\makebox(0,0)[r]{$R_C$}}
\qbezier(55,5)(65,20)(55,35)
\put(55,5){\vector(-2,-3){0}}
\put(63,20){\makebox(0,0)[l]{$U_{RE}$}}
\put(50,101){\circle{2}}
\put(47,101){\makebox(0,0)[r]{$U_{0C}$}}
\put(50,60){\circle*2}
\put(50,60){\line(1,0){20}}
\put(71,60){\circle2}
\put(66,40){\line(1,0){10}}
\put(71,58){\vector(0,-1){16}}
\put(73,50){\makebox(0,0)[l]{$U_a$}}
\end{picture}

\begin{picture}(160,80)
\put(0,40){\makebox(0,0)[l]{$U_e$}}
\put(14,40){\circle2}
\put(15,40){\vector(1,0){10}}
\put(30,40){\circle{10}}
\put(45,44){\makebox(0,0)[b]{$\scriptstyle U_{BE}$}}
\put(35,40){\vector(1,0){20}}
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\multiput(55,30)(20,0){2}{\line(0,1){20}}
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\put(75,40){\vector(1,0){15}}
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\multiput(90,30)(20,0){2}{\line(0,1){20}}
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\put(55,10){\makebox(0,0)[c]{$\scriptstyle -R_E$}}
\put(82.5,40){\circle*{1.5}}
\put(82.5,44){\makebox(0,0)[b]{$\scriptstyle I_{C}$}}
\put(110,40){\vector(1,0){10}}
\put(125,40){\circle{10}}
\put(125,55){\vector(0,-1){10}}
\put(125,57){\makebox(0,0)[b]{$U_{0C}$}}
\put(130,40){\line(1,0){9}}
\put(140,40){\circle{2}}
\put(143,40){\makebox(0,0)[l]{$U_{a}$}}

\end{picture}

\end{minipage}%
\begin{minipage}{10cm}
\begin{align*}
I_C &= I_S \cdot e^{\frac{U_{BE}}{U_T}} \\
U_{BE} &= U_e - U_{RE} = U_e - \frac{B+1}{B}I_C  R_E \approx U_e - I_CR_E \\
I_C &= I_S \cdot e^{\frac 1 {U_T}\left(U_e -ICR_E\right)}\\
U_a &= U_{0C} - I_C R_C \quad \Rightarrow \quad I_C = \frac{U_{0C} - U_a}{R_E} 
\end{align*}
\[ \boxed{\vphantom{\int} \quad U_a = U_{0C} - R_C I_S \cdot e^{\frac 1{U_T} 
\left(U_e - \frac{U_{0C} - U_a}{R_E}\cdot R_E\right)} \quad} \]
\end{minipage}%

\begin{minipage}{6cm}
\center
\begin{picture}(120,90)   % das ist die haesslichste Grafik aller Zeiten
\put(25,10){\vector(0,1){80}} 
\put(20,15){\vector(1,0){100}}
\put(23,80){\makebox(0,0)[r]{$U_a$}}
\put(110,7){\makebox(0,0)[c]{$U_e$}}
\put(24,60){\line(1,0){2}}
\put(22,60){\makebox(0,0)[r]{$\scriptstyle U_{0C}$}}
\put(25,60){\line(1,-1){45}}
\put(70,14){\line(0,1){2}}
\put(70,13){\makebox(0,0)[t]{$\scriptstyle U_{0C}\frac{R_E}{R_C}$}}
\qbezier(25,60)(35,60)(40,58)
\qbezier(40,58)(48,56)(48,15)
\qbezier(48,15)(48,15)(110,30)
\thicklines
\qbezier(25,60)(35,60)(43,58)
\qbezier(43,58)(73,25)(73,25)
\qbezier(73,25)(75,23)(110,33)
\thinlines
\put(50,68){\makebox(0,0)[r]{$\scriptstyle U_{RE}$}}
\put(60,45){\makebox(0,0)[l]{$\sim\frac{R_C}{R_E} = v'$}}
\qbezier(38,63)(38,58)(28,58)
\end{picture}
\end{minipage}%
\begin{minipage}{10cm}
\[u_e = \underbrace{\frac{(U_{0C} - U_a)R_E}{R_C}}_{U_{RE}} + \underbrace{U_T
\ln \frac{U_{0C}-U_a}{R_C \cdot I_S}}_{U_{BE}}\]
\end{minipage}%


\subsection{Kleinsignalverhalten}

\begin{minipage}{8cm}
\centering
\begin{picture}(170,85)
\put(0,60){\makebox(0,0)[l]{$x$}}
\put(159,60){\makebox(0,0)[l]{$y$}}
\put(14,60){\circle{2}}
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\put(52.5,60){\vector(1,0){22.5}}
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\multiput(27,80)(4,0){30}{\line(1,0){2}}
\end{picture}
\end{minipage}%
\begin{minipage}{8cm}
\[y = v \cdot u, \qquad u = x + ky\]
\[\boxed{\quad y = v(x + ky) \quad \vphantom{\int}}\]
\[y(1-kv) = v \cdot x \quad \Rightarrow \quad y = \frac{c}{1-kv}x = v'x\]
\end{minipage}%

\bigskip
\bigskip

\begin{minipage}{8cm}
\textbf{Begriffe:}

\smallskip

\begin{tabular}{ll}
$k$ & R"uckkopplungsfaktor \\[1ex]
$k\cdot v$ & Schleifenverst"arkung\\[1ex]
$g = 1 - k\cdot v$ & R"uckkopplungsgrad\\[1ex]
$r = \frac{1}{g} = \frac{1}{1 - k\cdot v} = \frac{v'}{v}$ &Regelfaktor
\end{tabular}
\end{minipage}%
\begin{minipage}{8cm}
\centering
\begin{picture}(170,125)
\put(0,70){\vector(1,0){170}}
\put(75,10){\vector(0,1){110}}
\qbezier(10,75)(95,73)(95,110)
\qbezier(95,30)(95,65)(140,65)
\multiput(95,30)(0,4){22}{\line(0,1){2}}
\put(160,66){\makebox(0,0)[t]{$kv$}}
\put(78,115){\makebox(0,0)[l]{$r$}}
\put(52,100){\makebox(0,0)[r]{$g$}}
\put(95,70){\line(-3,2){40}}
\put(95,70){\line(3,-2){40}}
\put(0,30){\line(1,0){30}}
\put(47.5,31){\makebox(0,0){stabil}}
\put(66,30){\vector(1,0){29}}
\put(132.5,31){\makebox(0,0){instabil}}
\put(110,30){\vector(-1,0){15}}
\put(155,30){\line(1,0){15}}
\put(37.5,11){\makebox(0,0){\small Gegenkopplung}}
\put(122.5,11){\makebox(0,0){\small Mitkopplung}}
\end{picture}
\end{minipage}%

\subsection{Mit- und Gegenkopplung}
\begin{center}
\begin{tabular}{p{7cm}|p{7cm}}
\textbf{Gegenkopplung} & \textbf{Mitkopplung} \\
\hline
\hline
$kv < 0$ & $kv > 0$ \\
$g = 1 - kv > 1 $ & $g = 1 - kv < 1 $\\
$|v'| < |v|$ & $|v'| > |v|$ \\
\hline
\multicolumn{2}{c}{\textbf{Anwendungen}}\\
\hline
Verst"arker: Reduzierung der Verzerrungen, Ver"anderung von Ein- und
Ausgangswiderstand, Stabilisierung 
&
Kippschaltungen, Oszillatoren, Erzeugung negativer Widerst"ande,
G"uteverbesserung von resonanten Schaltungen
\end{tabular}
\end{center}

\subsubsection*{Spezialf"alle}
\begin{tabular}{lll@{\qquad}l}
$kv= 1$ & $\Rightarrow$ & $v' \to \infty$ & Stabilit"atsgrenze
(Schwingungserzeugung)\\
$kv \gg 1$ & $\Rightarrow$ & $v' = \frac{v}{1-kv} \approx -\frac 1 k$ &
OPV-Schaltungen
\end{tabular}

\section{Gegenkopplungsarten}
\subsection{Allgemein}
Siehe Folie: {\small 
\href{http://www.iee.et.tu-dresden.de/iee/ge/student/materialien/ST/folien/feedb/feedb1.pdf}{http://www.iee.et.tu-dresden.de/iee/ge/student/materialien/ST/folien/feedb/feedb1.pdf}}

\subsection{Bei Transistorgrundstufen}

\begin{minipage}{8cm}
\centering
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\put(50,104){\makebox(0,0)[b]{$U_{0C}$}}
\end{picture}
\end{minipage}%
\begin{minipage}{8cm}
\centering
\begin{picture}(120,120)
\put(30,0){\line(0,1){50}}
\put(25,0){\line(1,0){10}}
\put(30,25){\circle{20}}
\put(20,25){\makebox(0,0)[r]{$U_{G}\Big\downarrow$}}
\put(50,57){\makebox(0,0)[b]{$R_{G}$}}
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\put(100,111){\circle2}
\put(97,111){\makebox(0,0)[r]{$U_{0C}$}}
\end{picture}
\end{minipage}%

\bigskip

\begin{minipage}{8cm}
\centering Serien-Stromgegenkopplung

Unwirksam bei Stromeinspeisung!
\end{minipage}%
\begin{minipage}{8cm}
\centering Parallel-Spannungsgegenkopplung

Unwirksam bei \emph{reiner} Spannungsansteuerung
\end{minipage}%

\section{Effekte der Gegenkopplung}
\subsection{Parameterempfindlichkeit (Sensitivity)}

\begin{minipage}{7cm}
\subsubsection*{Definition:}

\smallskip

\hfill
\begin{picture}(150,30)
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\put(50,10){\makebox(0,0)[c]{$a$}}
\put(46,6){\vector(1,1){10}}
\end{picture}
\end{minipage}%
\begin{minipage}{8cm}
\begin{tabular}{l@{\qquad\qquad }l@{\ }l}
$y = v(a) \cdot x$ &$v$: & beeinflu"sende Gr"o"se\\
& $a$: & Einflu"sgr"o"se
\end{tabular}
\[\boxed{\quad S_a^v = \frac{a\,dv}{v\,da} = \frac{d\ln v}{d \ln a}\quad }
\qquad\qquad \]
\end{minipage}%

\bigskip
\bigskip

\begin{minipage}{7cm}
\centering
\begin{picture}(170,85)
\put(0,60){\makebox(0,0)[l]{$x$}}
\put(159,60){\makebox(0,0)[l]{$y$}}
\put(14,60){\circle{2}}
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\multiput(27,80)(4,0){30}{\line(1,0){2}}
\end{picture}
\end{minipage}%
\begin{minipage}{9cm}
\begin{description}
\item[gegeben:] $S_a^v$, $v' = \frac{v(a)}{1-kv(a)} = v'(a)$
\item[gesucht:] $\displaystyle S_a^{v'} = \frac{dv'}{da} \frac{a}{v'} =
\frac{a}{v'}\frac{dv'}{dv}\frac{dv}{da} = \underbrace{\frac v {v'}
\frac{dv'}{dv}}_{S_v^{v'}} \underbrace{\frac a v \frac{dv}{da}}_{S_a^v}$
\end{description}
\end{minipage}%
\[\Rightarrow \quad \boxed{\quad  \vphantom{\int} S_a^{v'} = S_v^{v'} \cdot S_a^v  \quad} \qquad
\text{Kettenregel f"ur Empfindlichkeiten}\]

\[S_v^{v'} = \frac{v}{v'} \frac{dv'}{dv} =
\frac{\cancel{v}}{\frac{\cancel{v}}{1-kv}}
\frac{(1-\cancel{kv})+\cancel{vk}}{(1-kv)^{\cancel{2}}} = \frac{1}{1-kv} =
\frac 1 g\,, \qquad S_a^{v'} = S_a^v \frac{1}{1-kv} \]

\subsubsection*{Beispiel:}

\begin{minipage}{8cm}
\centering
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\put(60,50){\line(3,2){37.5}}
\put(60,100){\line(3,-2){37.5}}
\put(62,90){\makebox(0,0)[l]{$+$}}
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\put(70,33){\makebox(0,0)[t]{$R_2$}}
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\end{minipage}%
\begin{minipage}{8cm}
\centering
\begin{picture}(180,85)
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\end{minipage}%

\bigskip

\[u_a = v\cdot u_d = v(u_+ - u_-) \qquad\qquad k = \frac{R_1}{R_1+R_2}, \ u_+ = u_e,\
u_- = ku_a\]
\[v' = \frac{v}{1+kv}, \qquad S_a^{v'} = \frac{1}{1+kv}S_a^v, \qquad v = 10^4,\
k = \frac 1 2 \]
\[v' = \frac{10^4}{1+0{,}5\cdot 10^4} \approx \frac 1 k = 2\]
\paragraph{Empfindlichkeit:} $\displaystyle S_a^{v'} = \frac{1}{1+0{,}5\cdot
10^4}\cdot s_a^v = 2 \cdot 10^{-4} \cdot S_a^v$

\subsection{Eingangswiderstand}
\subsubsection{Parallel-Gegenkopplung (Miller-Effekt)}

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%%%
\put(226.25,40){\makebox(0,0){$\widehat{=}\vphantom{j}$}}
%%%
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\put(287,60){\makebox(0,0)[r]{$-i\!\downarrow$}}

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\end{center}

Verst"arker: $u_a = - v \cdot u_e, \quad v > 0$
\[i = \frac{u_a - u_e}{R} = - \frac{1+v}{R} u_e = \frac{1+\frac 1 v}{R}u_a\]

\subsubsection*{Beispiel:}

\begin{minipage}{6cm}
\centering
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\end{picture}

\bigskip

$R = 10\,\mathrm k\Omega$, $v = 10^5$, $i_{ev} = 0$
\end{minipage}%
\begin{minipage}{10cm}
\vspace{-1em}
\begin{align*}
u_a &= v \cdot u_d = - v \cdot u_e\\
u_e &= u_a + i_e R  && r_e = \frac{u_e}{i_e} = \frac{R}{1+v}\\
u_e(1+v) &\approx i_e R
\end{align*}
\[\boxed{\quad r_e = \frac{10^4\,\Omega}{1 + 10^5} = 0{,}1\,\Omega  \quad}\]
\end{minipage}%

\subsubsection*{Anwendungen}

\begin{enumerate}
\item \mbox{}

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\put(253,25){\makebox(0,0)[l]{$C(1+v)$}}
\end{picture}

\item \mbox{}

\begin{minipage}{4.5cm}
\begin{picture}(90,100)
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\put(55,40){\circle*{2}}
\put(45,40){\line(1,0){20}}
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\put(75,60){\circle*{2}}
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\end{picture}
\end{minipage}%
\begin{minipage}{10cm}
$C_{CB}$ \ldots parasit"are Kapazit"at

\bigskip

$C_{CB} = 0{,}5\,\mathrm{pF}$, \quad $v =  100$

\bigskip

$C_{CE} = (1+v) \cdot C_{BE} = 50\,\mathrm{pF} \widehat{=} \frac{1}{\omega
C_{CE}} = 32\,\Omega$ bei $f = 100\,\mathrm{MHz}$
\end{minipage}%
\end{enumerate}

\subsubsection{Seriengegenkopplung (Bootstrap-Effekt)}
\begin{minipage}{8cm}
\centering
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\begin{minipage}{8cm}
\[i_e = \frac{u_{ev}}{r_{ev}} = \frac{u_e - k \cdot u_a}{r_{ev}}, \qquad k
\approx \frac{R_1}{R_1+R_2}\]
\[u_a = v\cdot u_{ev} = v(u_e - ku_a), \qquad R_1 \parallel R_2 \ll r_{ev}
\vphantom{\frac a a}\]
\[u_a(1+kv) = vu_e, \qquad u_a = \frac{v}{1+kv}u_e = v' u_e\]
\end{minipage}%

\bigskip
\bigskip

\[i_e = \frac{1}{r_{ev}} \left(1 - \frac{kv}{1+kv}\right) u_e =
\frac{1}{r_{ev}}\frac{u_e}{1+kv} \qquad \Rightarrow \qquad r_e = r_{ev} (1+kv) = r_{ev} \cdot g \]

\paragraph{Beispiel:} $k = 1$ ($R_1 \to \infty$), $r_{ev} =
10\,\mathrm{k}\Omega$, $v = 10^{4} \Rightarrow  r_e = 10^8\,\Omega$

\subsubsection*{Anwendungen:}
\begin{minipage}{6cm}
\centering
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\end{picture}
\end{minipage}%
\begin{minipage}{8cm}
\[r_{ev} = r{BE}, \qquad v = \frac{u_a}{u_{ev}} = g_m \cdot R_E\]
\[k = 1 \quad \Rightarrow r_e = r_{ev}(1+g_mR_E) = {r_{BE} + bR_E} \]
\end{minipage}%


\bigskip

\begin{center}
\fbox{
\begin{minipage}{12.5cm}
\centering
\begin{tabular}{llll}
Parallel- & & verkleinert \\[-1ex]
 & Gegenkopplung & & den Eingangswiderstand\\[-1ex]
Serien- & & vergr"o"sert 
\end{tabular}
\end{minipage}%
}
\end{center}

\subsection{Ausgangswiderstand}

\begin{center}
\fbox{
\begin{minipage}{12.5cm}
\centering
\begin{tabular}{llll}
Spannungs- & & verkleinert \\[-1ex]
 & Gegenkopplung & & den Ausgangswiderstand\\[-1ex]
Strom- & & vergr"o"sert 
\end{tabular}
\end{minipage}%
}
\end{center}

\paragraph{Beispiel 1:} Verst"arker mit Spannungsgegenkopplung

\begin{minipage}{8cm}
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\put(70,50){\line(1,0){10}}
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\put(120,78){\makebox(0,0)[b]{$R$}}
\put(50,58){\makebox(0,0)[b]{$R_1$}}
\put(75,30){\makebox(0,0)[r]{$u_{ev}\Big\downarrow$}}
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\put(190,30){\line(1,0){20}}
\put(200,30){\circle{20}}
\put(210,30){\makebox(0,0)[l]{$\Big\uparrow i_{a}$}}
\end{picture}
\end{minipage}%
\begin{minipage}{8cm}
\[u_a = - v \cdot u_{ev} + (i_a - i)r_a \approx -v u_{ev} + i_a r_a, \quad i
\ll i_a \]
\[u_{ev} = \frac{R}{R+R_1} u_e + \frac{R_1}{R_1 + R}u_a\]
\[u_a = \underbrace{\frac{R}{R+R_1} \cdot
\frac{-v}{1+\frac{R_1}{R_1+R}v}}_{v'}u_e +
\underbrace{\frac{r_{av}}{1+\frac{R_1}{R_1+R}v}}_{r_a'}
i_a\]
\end{minipage}%

\begin{minipage}{7cm}
\center
\begin{picture}(110,100)
\put(0,40){\makebox(0,0)[l]{$u_e$}}
\put(15,40){\circle*3}
\put(15,40){\line(1,0){40}}
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\put(55,40){\circle*3}
\put(55,43){\makebox(0,0)[b]{$u_{ev}$}}
\put(35,37){\makebox(0,0)[t]{$\frac{R}{R_1+R}$}}
\put(55,40){\line(1,0){40}}
\put(55,40){\vector(1,0){22}}
\put(75,43){\makebox(0,0)[b]{$-v$}}
\put(95,40){\circle*3}
\qbezier(95,40)(75,20)(55,40)
\put(73,30){\vector(-1,0){0}}
\put(75,27){\makebox(0,0)[t]{$\frac{R_1}{R_1+R}$}}
\put(95,80){\line(0,-1){40}}
\put(95,80){\vector(0,-1){22}}
\put(95,80){\circle*3}
\put(98,60){\makebox(0,0)[l]{$r_{av}$}}
\put(95,83){\makebox(0,0)[b]{$i_{a}$}}
\put(98,40){\makebox(0,0)[l]{$u_{a}$}}
\end{picture}
\end{minipage}%
\begin{minipage}{9cm}
\[r_a' = \frac{r_a}{1+vk} = \frac{r_a}{g}, \qquad v' \approx -\frac{R}{R_1+R}
\frac{R_1+R}{R_1} = - \frac{R}{R_1}\]

\paragraph{Beispiel:} $k = 0{,}1 \to v' = 10$, $v= 10^5$, $ r_{av} =
100\,\Omega$
\[\Rightarrow r_{a}' = \frac{100\,\Omega}{1+10^4} \approx 0{,}01\,\Omega =
10\,\mathrm m\Omega\]
\end{minipage}%

\paragraph{Beispiel 2:} MOS-Stromquelle

\begin{minipage}{6cm}
\center
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\put(5,0){\line(0,1){60}}
\put(5,60){\line(1,0){30}}
\put(35,50){\thicklines\line(0,1){20}}
\multiput(38,52)(0,16){2}{\line(1,0){12}}
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\put(50,60){\line(0,-1){10}}
\put(50,40){\line(0,1){10}}
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\put(50,105){\vector(0,-1){20}}
\put(53,95){\makebox(0,0)[l]{$I_a$}}
\put(5,30){\circle{20}}
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\end{minipage}%
\begin{minipage}{8cm}
\centering
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\end{minipage}%

\paragraph{gesucht:} $i_a$ in Abh"angigkeit von $u_G$, $u_a$.

\begin{minipage}{6cm}
\center
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\end{picture}
\end{minipage}%
\begin{minipage}{10cm}
\[i_a = g_m \cdot u_{GS} + \frac{u_a-u_S}{r_{DS}}\]
\[u_s = R_S \cdot i_a\]
\[u_{GS} = u_G - U_S\]
\[i_a = \underbrace{\frac{g_m}{1+g_mR_s+\frac{R_S}{r_{DS}}}}_{g_m'}u_G +
\underbrace{\frac{1}{r_{DS}\left(1+g_mR_S+\frac{R_S}{r_{DS}} \right)}}_{g'_a =
\frac{1}{r'_a}}u_a\]
\end{minipage}%

\paragraph{Beispiel:} $g_m = 5\,\mathrm{mS}$, $R_S = 10\,\mathrm k\Omega$,
$r_{DS} = 20\,\mathrm k\Omega \quad \Rightarrow \quad r_a' = r_{DS} + R_S(g_mr_{DS} + 1) = 1{,}03\,\mathrm{M}\Omega$

\subsection{Arbeitspunktstabilisierung}

Temperaturabh"angigkeit von Bipolartransistoren.

\paragraph{Modellgleichungen:}
\begin{align*}
I_B = \cancelto{}{I_S} \frac{1}{\cancelto{}{B_F}}
\ e^{\frac{U_{BE}}{\cancelto{}{U_T}}} &= Y_1 (U_{BC}, T)\\
I_C = \cancelto{}{I_S} 
\ e^{\frac{U_{BE}}{\cancelto{}{U_T}}} &= Y_2 (U_{BE}, T)
\end{align*}
\paragraph{Kleinsignaldarstellung:}
\begin{align*}
i_B &= g_{BE} u_{BE} + \alpha_B \vartheta \qquad \vartheta = T - T_0\\[1ex]
g_{BE} &= \left.\frac{\partial I_B}{\partial U_{BE}}\right|_A =
\frac{I_{CA}}{B_FU_T}\\[1ex]
\alpha_B &= \left.\frac{\partial I_B}{\partial T}\right|_{T_0} =
\left.\frac{\partial}{\partial T}\left(\frac{I_C}{B_F}\right)\right|_{T_0}
\frac{I_{BA}}{U_T} = \frac{1}{B_F} \left.\frac{\partial I_C}{\partial
T}\right|_{T_0} - \left.\frac{I_{CA}}{{B_F}^2}\frac{\partial B_F}{\partial
T}\right|_{T_0} \\[1ex]
&\approx 0{,}07\frac{I_{BA0}}{\mathrm K} \qquad I_{BA0}\ldots\text{AP-Strom bei
Bezugstemperatur }T_0\\[1ex]
i_C &= g_m u_{BE} + \alpha_C \vartheta\\[1ex]
g_m &= \left.\frac{\partial I_C}{\partial U_{BE}}\right|_A =
\frac{I_{CA}}{U_T}\\[1ex]
\alpha_C &= \left.\frac{\partial I_C}{\partial T}\right|_{T_0} \approx
0{,}08\cdot \frac{I_{CA0}}{\mathrm K} \approx B_F \cdot \alpha_B
\end{align*}


\subsubsection*{Netzwerkmodell}

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\end{minipage}%
\begin{minipage}{6cm}
\[\boxed{\begin{array}{ccccc}
i_B &=& g_{BE} \cdot u_{BE}& +& \alpha_B \vartheta \\
i_C &=& g_{m} \cdot u_{BE} &+& \alpha_C \vartheta
\end{array}}
\]
\end{minipage}%

\bigskip

\begin{align*}
i_B &= g_{BE} \left(u_{BE} + \frac{\alpha_B}{g_{BE}}\vartheta \right) = g_{BE}
(u_{BE} + d_B \vartheta), & d_B &= \frac{\alpha_B}{g_{BE}} \approx 2\,
\frac{\mathrm{mV}}{\mathrm K}\\[1ex]
i_C &= g_m \left(u_{BE} + \frac{\alpha_C}{g_{m}}\vartheta \right) = g_m
(\underbrace{u_{BE} + d_C \vartheta}_{u_{BET}}),  & d_C &=
\frac{\alpha_C}{g_{m}} \approx 2{,}3\,
\frac{\mathrm{mV}}{\mathrm K}
\end{align*}

\bigskip

\begin{minipage}{7.5cm}
\centering
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\end{picture}
\end{minipage}%
\begin{minipage}{1cm}
\centering 
\bigskip
\smallskip
$\widehat{=}$
\end{minipage}%
\begin{minipage}{7.5cm}
\centering
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\end{picture}
\end{minipage}%

\bigskip

\hfill $d_C-d_B \approx 0{,}26\frac{\mathrm{mV}}{\mathrm K}$

\paragraph{Beispiel 1:} Basisspannungseinspeisung

\smallskip

$U_{0C}=10\,\mathrm V$,
$U_{BE0} = 0{,}65\,\mathrm V$, $R_C = 10\,\mathrm k\Omega$, $I_{CA} =
0{,}5\,\mathrm{mA}$, $B_F = b = 100$

\bigskip

\begin{minipage}{5cm}
\centering
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\put(76,0){\line(1,0){10}}
\end{picture}

\bigskip

\end{minipage}%
\begin{minipage}{11cm}
\centering
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\[u_a = - \alpha_C \vartheta R_C = - 0{,}08 \frac{0{,}5\,\mathrm{mA}}{\mathrm
K}\cdot 10\,\mathrm k\Omega = - 0{,}4\,\frac{\mathrm V}{\mathrm K} \cdot
\vartheta\]
\end{minipage}

\paragraph{Beispiel 2:} Basisstromeinspeisung

\bigskip

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\begin{align*}
u_a &= - (g_m u_{BE} + \alpha_C \vartheta) \cdot R_C \hspace{5cm} u_{BE} =
-\frac{\alpha_B \vartheta}{\frac{1}{R_B}+\frac{1}{r_{BE}}}\\
&= \left(\frac{g_m\alpha_B\vartheta r_{BE}}{1+\frac{r_{BE}}{R_B}} - \alpha_C
\vartheta\right) R_C =
\left(\frac{1}{1+\frac{r_{BE}}{R_B}}\right)\alpha_C\vartheta R_C = -
\frac{\frac{r_{BE}}{R_B}}{1+\frac{r_{BE}}{R_B}} R_C \alpha_C\vartheta
\end{align*}

\[\frac{r_{BE}}{R_B} = \frac{U_T}{I_{BA}} \cot \frac{I_{BA}}{U_{0C}-U_{BE0}} =
2{,}8\cdot 10^{-3}\]

\[ \Rightarrow\quad
u_a = -1\,\mathrm{mV} 
\frac{\vartheta}{\mathrm K}\]

\begin{center}
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\end{center}


\chapter{Operationsverst"arker}

\section{Aufbau und Grundmodell}
\begin{center}
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\put(16,25){\makebox(0,0)[r]{$u_d$}}
\put(224,25){\makebox(0,0)[l]{$u_a$}}

\put(60,55){\makebox(0,0)[c]{\small Diff.-Verst"arker}}
\put(120,55){\makebox(0,0)[c]{\small Treiber}}
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\end{picture}
\end{center}

\paragraph{Grundmodell:} $u_a = v \cdot u_d + r_a i_a= v(u_+ - u_-) + r_ai_a$

\begin{minipage}{8cm}
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\put(65,64){\makebox(0,0)[b]{$i_a$}}
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\end{minipage}%
\begin{minipage}{8cm}
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\end{minipage}%

\bigskip

im Bildbereich:
\[\underline U_a(s) = \frac{v}{3+s\tau} \underline U_d + r_a \cdot \underline
I_a, \qquad \tau = \frac{1}{2\pi f_{\infty}} = \frac{1}{\omega_{\infty}}\]


\section{Analyseverfahren (idealer OPV)}

$r_e \to \infty$, $I_+ = I_- = 0$, $r_a \to 0$, $v \to \infty$





\end{document}

